Originally posted by: Narmer
Originally posted by: thesurge
Originally posted by: Narmer
Originally posted by: hypn0tik
Originally posted by: Narmer
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If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.
Or am I wrong.
Sure. And instead of choosing 'e' to represent the natural base, we could have chosen 'z'. Instead of choosing i^2 = -1, we could have chosen e^2 = -1.
What's your point?
Edit: z^pi*e + 1 = 0
My point is that pi=3.1419..., which is a ratio
But in the case of Euler's identity, pi=180 degrees.
The two uses of the symbol pi have very different functions.
Err... e^{ix}=cos(x)+isin(x)
http://en.wikipedia.org/wiki/Euler%27s_formula#Using_calculus
Simple proof. Subsitute "pi" in the equation and OMG you get TEH identity!
I know that, Genius, that's why I'm asking the question of why the euler's identity would make people see pi(3.1419...) when they are actually seeing pi(degrees). At worst, it's a perversion. Hence, the identity is not as beautiful as many see it. It can be beaufitul, but only if you believe something that really isn't what it espouses to be.
We're seeing pi (3.1419...) radians. What's the problem here?
