Isn't the most famous equation in mathematics a perversion?

Narmer

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If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.
 

ElFenix

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you're wrong.

a squared plus b squared = c squared is the most famous equation
 

hypn0tik

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Originally posted by: Narmer
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If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.

Sure. And instead of choosing 'e' to represent the natural base, we could have chosen 'z'. Instead of choosing i^2 = -1, we could have chosen e^2 = -1.

What's your point?

Edit: z^pi*e + 1 = 0
 

Syringer

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Aug 2, 2001
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Originally posted by: Narmer
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If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.

Just a moron.
 

hypn0tik

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Jul 5, 2005
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Originally posted by: JohnCU
Originally posted by: ElFenix
you're wrong.

a squared plus b squared = c squared is the most famous equation

actually, you're wrong. sorry.

If ElFenix was an EE, he'd appreciate the beauty of Euler's expression.
 

Narmer

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Aug 27, 2006
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Originally posted by: hypn0tik
Originally posted by: Narmer
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If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.

Sure. And instead of choosing 'e' to represent the natural base, we could have chosen 'z'. Instead of choosing i^2 = -1, we could have chosen e^2 = -1.

What's your point?

Edit: z^pi*e + 1 = 0

My point is that pi=3.1419..., which is a ratio

But in the case of Euler's identity, pi=180 degrees.

The two uses of the symbol pi have very different functions.
 

Rubycon

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Aug 10, 2005
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Originally posted by: Narmer

My point is that pi=3.1419..., which is a ratio

But in the case of Euler's identity, pi=180 degrees.

The two uses of the symbol pi have very different functions.

If your pies are only 180 degrees they are going to be mushy. Perhaps that's Centigrade. :laugh:

 

thesurge

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Dec 11, 2004
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Originally posted by: Narmer
Originally posted by: hypn0tik
Originally posted by: Narmer
link

If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.

Sure. And instead of choosing 'e' to represent the natural base, we could have chosen 'z'. Instead of choosing i^2 = -1, we could have chosen e^2 = -1.

What's your point?

Edit: z^pi*e + 1 = 0

My point is that pi=3.1419..., which is a ratio

But in the case of Euler's identity, pi=180 degrees.

The two uses of the symbol pi have very different functions.

Err... e^{ix}=cos(x)+isin(x)
http://en.wikipedia.org/wiki/Euler%27s_formula#Using_calculus

Simple proof. Subsitute "pi" in the equation and OMG you get TEH identity!

 

Narmer

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Aug 27, 2006
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Originally posted by: thesurge
Originally posted by: Narmer
Originally posted by: hypn0tik
Originally posted by: Narmer
link

If you look at the five components of Euler's identity: pi, 1, 0, e, and i. You can see that only one component, pi, isn't the real pi that we think of. Instead, pi in this case simply represents 180 degrees. But degrees can be represented by any other symbol, therefore pi isn't really pi in this instance.

Or am I wrong.

Sure. And instead of choosing 'e' to represent the natural base, we could have chosen 'z'. Instead of choosing i^2 = -1, we could have chosen e^2 = -1.

What's your point?

Edit: z^pi*e + 1 = 0

My point is that pi=3.1419..., which is a ratio

But in the case of Euler's identity, pi=180 degrees.

The two uses of the symbol pi have very different functions.

Err... e^{ix}=cos(x)+isin(x)
http://en.wikipedia.org/wiki/Euler%27s_formula#Using_calculus

Simple proof. Subsitute "pi" in the equation and OMG you get TEH identity!


I know that, Genius, that's why I'm asking the question of why the euler's identity would make people see pi(3.1419...) when they are actually seeing pi(degrees). At worst, it's a perversion. Hence, the identity is not as beautiful as many see it. It can be beaufitul, but only if you believe something that really isn't what it espouses to be.
 

JohnCU

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Dec 9, 2000
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Originally posted by: hypn0tik
Originally posted by: JohnCU
Originally posted by: ElFenix
you're wrong.

a squared plus b squared = c squared is the most famous equation

actually, you're wrong. sorry.

If ElFenix was an EE, he'd appreciate the beauty of Euler's expression.

indeed, that god damn expression is amazing. i remember the first time i studied it... thought i'd never use it again but was i wrong.
 

JohnCU

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Dec 9, 2000
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this equation relates the 5 most important fundamental numbers, how can it not be the most famous?
 

Narmer

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Aug 27, 2006
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Originally posted by: hypn0tik
OP, I suggest you read this.

I know the identity is correct but...others may think that they can simply plug in scalar pi and out will come 0... Never mind, I think I'll leave this one alone.

 

JohnCU

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Dec 9, 2000
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Originally posted by: Narmer
Originally posted by: hypn0tik
OP, I suggest you read this.

I know the identity is correct but...others may think that they can simply plug in scalar pi and out will come 0... Never mind, I think I'll leave this one alone.

what?
 

BrownTown

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Dec 1, 2005
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a. this is the most famous and most elegant of all mathematical formulas

b. how the heck do you not know what a radian is dude !?!?!?, degrees are just a random number set up becasue it is easy to work with, radians are the unit that actually has mathematical sense and pi radians in half a circle.

EDIT: jsut think of it this way, what is the diamater of the unit circle? = 2pi, what is half that, yeah thats right pi. pi = 180degrees.
 

Narmer

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Aug 27, 2006
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Originally posted by: JohnCU
Originally posted by: Narmer
Originally posted by: hypn0tik
OP, I suggest you read this.

I know the identity is correct but...others may think that they can simply plug in scalar pi and out will come 0... Never mind, I think I'll leave this one alone.

what?

I'm saying disregard the question. Forget it. Forget I asked it.
 

Oscar1613

Golden Member
Jan 31, 2001
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Originally posted by: Narmer
Originally posted by: hypn0tik
OP, I suggest you read this.

I know the identity is correct but...others may think that they can simply plug in scalar pi and out will come 0... Never mind, I think I'll leave this one alone.

because you can :confused:
 

Narmer

Diamond Member
Aug 27, 2006
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Originally posted by: BrownTown
lol, i bet youd like us to forget it after making such a dumb post :p.

If it's such a dumb post, then I'd like you to do me a small favor. I'd like you to decouple the entire equation and show it in all it's ugliness. Show us the meat and potatoes of Euler's identity. I'll give you a head start:

e^i(pi) +1=0

where e^i(pi)= cos(pi) +isin(pi)=-1

But a^x>0>-1. If you've taken modern analysis (which I haven't) or number theory, perhaps you can enlighten me and the average joe on this equation by explaining exactly what i is.

I'm not saying the equation isn't beautiful (in it's simplicity), but there's a wholly complex dimension that undermines such beauty. Perhaps I'm being more philosophical than mathematical, but that's precisely my point.