is this reaction possible

[polarbear6]

as we know asprin has a carboxlic acid group(-cooh)

so if we treat it with water
(-cooh + (-)oh)
can we get carbon dioxide ??

 

[polarbear6]

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

 

[polarbear6]

cmmon ppl 18 views and no replies 🙁

 

[Gibsons]

No. At neutral pH, the H disassociates and you have COO- and H+. The carbon stays where it is.

 

[Cogman]

Originally posted by: ganesh1
cmmon ppl 18 views and no replies 🙁

We aren't going to do your homework for you. And we are MUCH more likely not to respond if you repeatedly bump your own thread up. This is HT, bumps are not needed.

 

[polarbear6]

i have much more material available for my homework i just needed to confirm something to my friend ok

and besides i dont even bother doing my homework

 

[dkozloski]

Throw an aspirin tablet in a glass of water and see if it fizzes.

 

[KIAman]

Cut a piece of Alka-Selzer into an aspirin sized tablet, and trick your "friend" into thinking this works then watch him fail his class. Sounds like fun.

 

[polarbear6]

well we had a exam and i wrote one answer he wrote one

and we know our lecturers are too lazy to correct our papers

and we just dont like to ask our lecturer
i said co2 will not be released

cause i thought that thye phenol group is to stable for the cooh group to separate out and he said it will come out 😛

and i have seen a aspirin in water and it doesnt fizze out

 

[Gibsons]

Originally posted by: ganesh1
well we had a exam and i wrote one answer he wrote one

and we know our lecturers are too lazy to correct our papers

and we just dont like to ask our lecturer
i said co2 will not be released

cause i thought that thye phenol group is to stable for the cooh group to separate out and he said it will come out 😛

and i have seen a aspirin in water and it doesnt fizze out

it's not that the phenyl group is stable (it is stable but that's not the issue), it's that there's a carbon-carbon bond that holds the COO- to the ring. C-C bonds don't break so easily (usually).