Is it possible to solve this equation?

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Dari

Lifer
Oct 25, 2002
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(150R^t)-10(sum(R^t,t,1,t-1))-10t=0
where R=1.1

I tried using the normal solve technique in Matlab and it produced an error.

For the curious, this is a country living off its foreign assets to pay its seconday deficit. Time t is the period before they switch to inflationary financing.
The lecture notes had a much simpler function that I believed was incorrect: 150-10t=0
 

JTsyo

Lifer
Nov 18, 2007
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would sum(R^t,t,1,t-1) be the same as R^t+2*t?

Around 8.5 would be the min, won't reach zero, I think.
 

ConwayJim

Senior member
Dec 16, 2004
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Originally posted by: Dari
(150R^t)-10(sum(R^t,t,1,t-1))-10t=0
where R=1.1

I tried using the normal solve technique in Matlab and it produced an error.

For the curious, this is a country living off its foreign assets to pay its seconday deficit. Time t is the period before they switch to inflationary financing.
The lecture notes had a much simpler function that I believed was incorrect: 150-10t=0

hmmm...it could be solved....and i use this term loosely...COULD...
 

TuxDave

Lifer
Oct 8, 2002
10,571
3
71
Originally posted by: Dari
(150R^t)-10(sum(R^t,t,1,t-1))-10t=0
where R=1.1

I tried using the normal solve technique in Matlab and it produced an error.

For the curious, this is a country living off its foreign assets to pay its seconday deficit. Time t is the period before they switch to inflationary financing.
The lecture notes had a much simpler function that I believed was incorrect: 150-10t=0

150-10t=0
t = 15

Plugging it back to your original equation:

168.8624 = 0

Looks like that was a pretty shitty simplification.

Also using the powers of excel and expanding to to 100, the answer is not converging. So your original equation is broken.
 

leftyman

Diamond Member
Sep 15, 2000
7,073
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this should be a multiple choice question. Then at least I could guess and maybe look smart. :thumbsup:
 

Dari

Lifer
Oct 25, 2002
17,133
38
91
Originally posted by: TuxDave
Originally posted by: Dari
(150R^t)-10(sum(R^t,t,1,t-1))-10t=0
where R=1.1

I tried using the normal solve technique in Matlab and it produced an error.

For the curious, this is a country living off its foreign assets to pay its seconday deficit. Time t is the period before they switch to inflationary financing.
The lecture notes had a much simpler function that I believed was incorrect: 150-10t=0

150-10t=0
t = 15

Plugging it back to your original equation:

168.8624 = 0

Looks like that was a pretty shitty simplification.

Also using the powers of excel and expanding to to 100, the answer is not converging. So your original equation is broken.

Right. I think it should be this instead:
(150R^t)-10(sum(R^t,t,1,t-1))-10=0

EDIT: I'm trying to account for the interest accrued in each period from the remaining assets. It should be close to 15, but a bit more.
 
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