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Is a 60W bulb in a 100W socket safe?

If you are placing a lower wattage bulb in a socket built for a higher wattage and the voltage is the same for the two bulbs, then yes, it's perfectly fine.
 
Originally posted by: Legend
So there's no such thing as a 100 W socket? The power applied is variable?
Click to expand...

sre you talking about a normal light socket?

because they cna take ANY light bulb from say 15w to 1000w
 
A lower wattage bulb is safe, but higher may not be.

For those of you that dont understand, some lamps and fixutres say "rated for XXXw bulb"
 
Originally posted by: Legend
So there's no such thing as a 100 W socket? The power applied is variable?
Click to expand...

Yes, light fixtures (sockets) are rated at a maximum wattage. Many ceiling fans, for instance, have sockets rated at 75 W per bulb. Many enclosed fixtures (sockets) are rated at 60W because of heat buildup. Also, some sockets may have smaller wiring leading to them that a 100W bulb might be a potential fire hazzard, but not likely as a 100W bulb pulls around one amp and it takes one hell of a small wire to not withstand one amp! 🙂
 
Originally posted by: Anubis
Originally posted by: Legend
So there's no such thing as a 100 W socket? The power applied is variable?
Click to expand...

sre you talking about a normal light socket?

because they cna take ANY light bulb from say 15w to 1000w
Click to expand...

But the wires used to construct the fixture may only be rated to a certain wattage. If a bulb draws 500 watts, and the wires are rated to 100 watts - you're gonna have a fire.

As Engineer said, 60w bulbs in a socket rated at 100 will be fine, as long as voltage is the same.
 
Originally posted by: Bozono
A Legend in your own mind. Should be fine, though it's life will likely be shortened.
Click to expand...

wtf are you people talking about?!?

OP if you are talking about a light fixture that's rated for a maximum of 100w then you can use any bulb that's 100w or under.
 
It's built into the ceiling.

It wouldn't give the 60W bulb any light. The bulb works for a lamp so it's not the bulb. Unfortunately I can't test the old 100W bulb anywhere else. I just moved into this apartment.
 
"I am not able rightly to apprehend the kind of confusion of ideas that could provoke such a question."

Charles Babbage
 
Nevermind, It works now.

Sad thing is I'm a computer engineer student. They don't teach us the simplest things about hardware.

So

Power = I*R^2
V = I*R

If V = 120, and R is variable, I didn't understand that current is changing.
 
For energy and heat conservation reasons, it is best to use the lowest wattage bulb that satisfies your lighting requirements. There is no harm in using a lower wattage bulb in a socket.
 
Originally posted by: Legend
Nevermind, It works now.

Sad thing is I'm a computer engineer student. They don't teach us the simplest things about hardware.

So

Power = I*R^2
V = I*R

If V = 120, and R is variable, I didn't understand that current is changing.
Click to expand...

It isn't really that simple because your light bulb isn't purely resistive and your using AC current.
 
Originally posted by: Legend
Nevermind, It works now.

Sad thing is I'm a computer engineer student. They don't teach us the simplest things about hardware.

So

Power = I*R^2
V = I*R

If V = 120, and R is variable, I didn't understand that current is changing.
Click to expand...

uh, if R is variable, then i doesnt have to change 😕

If R is fixed then i will change depending on voltage or power.
 
It isn't really that simple because your light bulb isn't purely resistive and your using AC current.
Click to expand...

Ok, that makes more sense.

uh, if R is variable, then i doesnt have to change

If R is fixed then i will change depending on voltage or power.
Click to expand...

Both bulbs are 120 V. Voltage is constant. I was assuming that resistance was purely changing the power and current was constant. With that in mind, V=I*R would not make sense because R changes while I and V remain constant.

In math:

120 = 5 * x
120 = 5 * y

y cannot equal x

thus the equations are false
 
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