- Dec 5, 2000
- 43,804
- 46
- 91
the last octet of an IP address has to be 1-255, correct?
Well, I'm trying to run a ventrilo or teamspeak server from my PC which has a dynamic IP address. I just want it seto up so my friend and I can talk to eacher other through it for a few hours while playing games online.
So I set up the servers and go to whatismyip.org and it says my IP address is #.#.#.0.
THe other IP checker sites say the same thing.
My friend can't connect. It may be a firewall/NAT problem on my end but I think I have everything set to allow those programs and ports.
The IP address is really throwing me off though. How can I have 0 as my 4th octet?
Well, I'm trying to run a ventrilo or teamspeak server from my PC which has a dynamic IP address. I just want it seto up so my friend and I can talk to eacher other through it for a few hours while playing games online.
So I set up the servers and go to whatismyip.org and it says my IP address is #.#.#.0.
THe other IP checker sites say the same thing.
My friend can't connect. It may be a firewall/NAT problem on my end but I think I have everything set to allow those programs and ports.
The IP address is really throwing me off though. How can I have 0 as my 4th octet?
