if you fell into a pool of lava...

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Eli

Super Moderator | Elite Member
Oct 9, 1999
50,419
8
81
Originally posted by: MercenaryForHire
Originally posted by: dullard
Originally posted by: apoppin
are you sure would even SINK in liquid rock?

i think not . . . you'd grill pretty quick laying on a 2,000 degree F bed.
Someone is finally thinking.

The specific gravity of lava is >2 Since our bodies are mostly water, our specfic gravity is ~1. Thus we would not sink in the lava.

Hey, good point. Think of how hard belly-flopping off the high dive would hurt - now double the impact. :confused:

- M4H
Yeah. Ouch.

Lots of variables... If you went in feet first, I'd bet you would at least disappear into the lava.

I guess I don't really know though.
 

apoppin

Lifer
Mar 9, 2000
34,890
1
0
alienbabeltech.com
Originally posted by: Eli
Originally posted by: apoppin
Originally posted by: Eli
Originally posted by: vi_edit
Depending on the size/volume of the pool, you'd maybe pass out from pain/shock before you even hit it. The abient temperature around it depending on the size would probably be enough to make you combust before you even hit the <Dr Evil> Liquid hot mag ma </Dr Evil>.
Good point.

The problem is that we're all imagining different scenarios. There are many, many different types.. or stages rather, of magma/lava.

If the pool was big, deep and hot(liquid) enough, and you "fell in".. yes, you would go..... *bloop*.

Originally posted by: dullard
Originally posted by: apoppin
are you sure would even SINK in liquid rock?

i think not . . . you'd grill pretty quick laying on a 2,000 degree F bed.
Someone is finally thinking.

The specific gravity of lava is >2 Since our bodies are mostly water, our specfic gravity is ~1. Thus we would not sink in the lava.
Yes, if somehow you were set gently into a pool of lava, you would not sink.

That's not generally how someone would enter a pool of lava, though. :p

if you fell from 50 feet you still would not "sink" . . . not very far and it wouldn't make any difference. :p
:roll:
I'm listening, but I'm failing to understand how ~150lbs wouldn't make a splash, even in lava? Given a far enough fall, that is...

I'm thinking of the ultra-liquid, activly boiling kind. Not anything that is any distance away from the source and has therefor cooled.

well i walked right up to a pool of ultra hot liquid bubling orange-yellow lava and [then backed up and] threw a rock in . . . it really doesn't "sink" . . . more like "plops" [it's way thicker even than molasses]:Q

:shocked:

Hawaii isn't that far . . . next time you're on the Big Island, 'drop in' :D

and i was kidding about anakin
:roll:

edit
Hot Lava

[Performed by Perry Farell and D.V.D.A.]

Baby, every time we kiss, Hot Lava
And every time that we make love, that's Lava, Hot Lava
It's lava so hot, it makes me sweat
And lava so warm, it's red and wet
Mountain is rumbling, We must find a safer place

Soon half of Pele, Will fall upon your face
Great Nectar of the Gods spews far from Pinatabo
Mixed with a Women's Sweat, it makes the Lava we know
Baby, every time we kiss, Hot Lava
And every time that we make love, that's Lava, Hot Lava
It's lava so hot, it makes me sweat
And lava so warm, it's red and wet

Burnin' through the forest, Where Red hot lava flows
Rolls down the islands body, and into the ocean below
When it meets the cool, cool water, there's a big flow of the living
Rich magma flowing into a sobiquious environment, Produces Pillow Lava
And starts a pressure of sea water
Tends to inhabit the vesical size of the basalt
Baby, every time we kiss, Hot Lava
And every time that we make love, that's Lava, Hot Lava
It's lava so hot, it makes me sweat
And lava so warm, it's red and wet

And after the eruption, you lay dormant for a while
Let's just hold each other and talk, For now, Pele sleeps
Baby, every time we kiss, Hot Lava
And every time that we make love, that's Lava, Hot Lava
It's lava so hot, it makes me sweat
And lava so warm, it's red and wet
Baby, every time we kiss, Hot Lava
And every time that we make love, that's Lava, Hot Lava
It's lava so hot, it's red and wet
And lava so warm it makes me sweat.
 

Eli

Super Moderator | Elite Member
Oct 9, 1999
50,419
8
81
Originally posted by: apoppin

well i walked right up to a pool of ultra hot liquid bubling orange-yellow lava and [then backed up and] threw a rock in . . . it really doesn't "sink" . . . more like "plops" [it's way thicker even than molasses]:Q

:shocked:

Hawaii isn't that far . . . next time you're on the Big Island, 'drop in' :D

and i was kidding about anakin
:roll:
Hmm, yeah, I guess I need to visit sometime. ;)

Clearly don't get a good enough picture by seeing it on TV and such.. Either that or I just wasn't paying enough attention.

I can imagine that though. Almost like... very wet/saturated sand in a way? If you threw a rock at it, it wouldn't "sink".. But if you set the rock in it, it would slowly be covered/absorbed..
 

dug777

Lifer
Oct 13, 2004
24,778
4
0
head first, if it was from a decent height, youd break your neck i guess...
 

nccr

Member
Jun 9, 2001
105
0
76
It would definitely hurt. No question about that. To die though...I think would take a couple years until I was shot by lightning by some old deformed man with leprosy. Yeah...
 

apoppin

Lifer
Mar 9, 2000
34,890
1
0
alienbabeltech.com
Originally posted by: Eli
Originally posted by: apoppin

well i walked right up to a pool of ultra hot liquid bubling orange-yellow lava and [then backed up and] threw a rock in . . . it really doesn't "sink" . . . more like "plops" [it's way thicker even than molasses]:Q

:shocked:

Hawaii isn't that far . . . next time you're on the Big Island, 'drop in' :D

and i was kidding about anakin
:roll:
Hmm, yeah, I guess I need to visit sometime. ;)

Clearly don't get a good enough picture by seeing it on TV and such.. Either that or I just wasn't paying enough attention.

I can imagine that though. Almost like... very wet/saturated sand in a way? If you threw a rock at it, it wouldn't "sink".. But if you set the rock in it, it would slowly be covered/absorbed..

pictures don't really convey the feeling of being close to an active lava flow . . . dangerous, weird, strangely beautiful and UNconfortable due to difficulties breathing. Molton rock is so unlike anything else . . . it really "flows" and "splatters" and has all the characteristics of liquid but is still extremely thick.

it's an experience to never forget and well worth the visit . . just don't get too close!
 

dullard

Elite Member
May 21, 2001
25,989
4,598
126
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.

 

Vegitto

Diamond Member
May 3, 2005
5,234
1
0
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.


Dude... Over a minute of excruciating pain. I'm sure the sadomachosists (I can't spell, damnit!) will be eager to jump into the lava, now.
 

apoppin

Lifer
Mar 9, 2000
34,890
1
0
alienbabeltech.com
Originally posted by: Vegitto
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.


Dude... Over a minute of excruciating pain. I'm sure the sadomachosists (I can't spell, damnit!) will be eager to jump into the lava, now.

the instant you hit the lava your skin starts to vaporize and your hair catches fire. Your face would burn off and lava would probably enter your open mouth and eye sockets. it wouldn't be pretty and it wouldn't take long for massive SHOCK. i doubt your brain would still be functioning for even a minute. ;)

strange . . . a google search really doesn't have much about death by lava. :p
:roll:
 

Yossarian

Lifer
Dec 26, 2000
18,010
1
81
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.

you really need to get out more. besides which your math is totally pointless since your fvcking head will melt/burn the instant it touches lava.
 

Injury

Lifer
Jul 19, 2004
13,066
2
81
When I worked in an iron foundry, the iron furnaces had to be kept at at least 2200 degrees to keep the iron molten. So there's no way lava could be less than a few thousand degrees, I'd think.

At a mere 1200 degrees or so, anything thrown into the furnace that wasn't metallic would catch fire about 2 feet before reaching the molten metal. This leads me to believe that a person would probably be burning by the time they landed on the metal, be in shock within 10 seconds of falling in (not just being on the molten metal, knowing you're going in.) and be dead or beyond recovery within 20 seconds.

The body would probably be only bone by a minute, provided there is ample room for the steam created from the body to escape, and the bone would probably be gone in a couple of minutes.
 

xSkyDrAx

Diamond Member
Sep 14, 2003
7,706
1
0
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.

lmao only on ATOT would you find a math equation explaining how fast you would die if you were submerged in molten lava :thumbsup:
 

xSkyDrAx

Diamond Member
Sep 14, 2003
7,706
1
0
Originally posted by: apoppin
Originally posted by: Vegitto
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.


Dude... Over a minute of excruciating pain. I'm sure the sadomachosists (I can't spell, damnit!) will be eager to jump into the lava, now.

the instant you hit the lava your skin starts to vaporize and your hair catches fire. Your face would burn off and lava would probably enter your open mouth and eye sockets. it wouldn't be pretty and it wouldn't take long for massive SHOCK. i doubt your brain would still be functioning for even a minute. ;)

strange . . . a google search really doesn't have much about death by lava. :p
:roll:

Only because there isnt enough studies on it. People should really study this in greater depth :p
 

Sukhoi

Elite Member
Dec 5, 1999
15,346
106
106
Originally posted by: dullard
Originally posted by: Reck
how long do you think it'd take to die? i've always wondered...
Damn it, I couldn't stop thinking about this. Math time:

Assume:
[*]Entire head is submerged into lava somehow. You really might not die if just your feet are submerged. I bet you could get your head in temporarily, even though you would float (before you burn up).
[*]Lava is 1800°F.
[*]Head is initially 98°F.
[*]Head has the thermal properties of water.
[*]You die if the center of your brain reaches 110°F. I'm just giving a rough estimate here, but I know if fevers reach 110°F it can be quite deadly.
[*]Your head is a cylinder of r=3.5 inch diameter.
[*]Ignore heat transfer through the top of your head and heat transfer to your neck.

The assumptions give this partial differential equation model:

(1/r)*d/dr [r dT/dr] = (1/A) * dT/dt

Where r=radius, T=temperature as a function of radius and time, t=time, and A=1.45*10^-7 m^2/sec (thermal properties of water).

Boundary conditions: T(r=3.5)=1800°F and dT/dr = 0 at r=0.
Initial condition: T(r,0)=98°F.

Use separation of variables, integration, and knowledge of the Bessel equation to solve. No, I won't type it out. Look it up. Solution is (f-you if you find a goof, I'm just doing it quickly while listening to Tom Waits which is always a distraction):

T(r=0,t)=98°F +1702°F*(1-exp(-t/9400 sec))

Thus after 67 seconds, the temperature in the center of your brain is 110°F. You are fully dead. Sure before that time elapsed, the outer portions of your brain will die. But parts of your brain will still function for 67 seconds.

Dude you're depressing me. I could do that stuff three months ago and now I can hardly remember it. :(
 

apoppin

Lifer
Mar 9, 2000
34,890
1
0
alienbabeltech.com
Originally posted by: Injury
When I worked in an iron foundry, the iron furnaces had to be kept at at least 2200 degrees to keep the iron molten. So there's no way lava could be less than a few thousand degrees, I'd think.

At a mere 1200 degrees or so, anything thrown into the furnace that wasn't metallic would catch fire about 2 feet before reaching the molten metal. This leads me to believe that a person would probably be burning by the time they landed on the metal, be in shock within 10 seconds of falling in (not just being on the molten metal, knowing you're going in.) and be dead or beyond recovery within 20 seconds.

The body would probably be only bone by a minute, provided there is ample room for the steam created from the body to escape, and the bone would probably be gone in a couple of minutes.

Lava's temp is about that at your foundry . . . after the bone is gone it'd be ash. :Q

i guess the ancient Hawaiians knew something about this in their sacrifices to Pele
:shocked:

i don't think we need any 'studies' . . . . .

. . . maybe a new 'reality show' :p
:roll:


sorry


:D