i need help with integration

[Cha0s]

can someone show me the steps how to integrate
e^(Sqrt[x+1])
thanks

 

[KLin]

42

 

[Hankysmoo]

Originally posted by: Cha0s
can someone show me the steps how to integrate
e^(Sqrt[x+1])
thanks

Pull out Ti-89
input e^(Sqrt[x+1]) using the intergrate function
...
have fun!

 

[Cha0s]

i need to learn the steps not the answer

 

[Brackis]

Originally posted by: Cha0s
can someone show me the steps how to integrate
e^(Sqrt[x+1])
thanks

Just make sure e and [X+1] go to the same schools and have the same restroom, all set!

 

[Semidevil]

I dont quite remember, but maybe substituion....change it to e^u du,

and integreate root(x+1) also somewhere along the line...

i'm not sure, but someone else can help the rest

 

[MeanMeosh]

Originally posted by: Brackis

Originally posted by: Cha0s
can someone show me the steps how to integrate
e^(Sqrt[x+1])
thanks

Just make sure e and [X+1] go to the same schools and have the same restroom, all set!

let us not forget the water fountains

 

[Cha0s]

damn, i need some serious replies.

 

[BRObedoza]

nm

 

[Goosemaster]

Show us your work and we will help with your homework🙂

 

[sandmanwake]

Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

 

[chuckywang]

multiply 2*sqrt(x+1)/(2*sqrt(x+1)) and then integrate by parts.

 

[sisq0kidd]

Well, if the group you want to integrate into are whites, dress like all of your clothes have been washed a bagillion times so they have that faded look, if they are black, dress like you fell in a puddle of chrome, if they are asian, dress like... ermm, dunno how asians dress, if they are hispanic, dress like you think you are black sans the chrome... hope this helps... integration is vital to being accepted...

 

[Goosemaster]

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

hint>! 😛

 

[Semidevil]

Originally posted by: Goosemaster

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

hint>! 😛

that's what I said!! kinda.....


😛

 

[chuckywang]

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

It's not tha simple, since du/dx is 1/(2sqrt(x+1))

 

[Goosemaster]

Originally posted by: chuckywang

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

It's not tha simple, since du/dx is 1/(2sqrt(x+1))

😛 Stop doing his hw for him until he responds..😛

 

[sandmanwake]

Originally posted by: chuckywang

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

It's not tha simple, since ...

That's why it's called a hint and not I'm giving you the answer, so no need to think.

 

[OulOat]

Never a better time

 

[Goosemaster]

Originally posted by: OulOat
Never a better time

😎

 

[chuckywang]

Originally posted by: sandmanwake

Originally posted by: chuckywang

Originally posted by: sandmanwake
Why not let u=(x+1)^(1/2) then use the fact that the derivative of e^x=e^x, substitute where necessary. That's all the hint you get for your homework.

It's not tha simple, since ...

That's why it's called a hint and not I'm giving you the answer, so no need to think.

A better hint would be to integrate by parts.

 

[Cha0s]

I got it myself, lol

 

[blustori]

lol all of those ppl that said u substitution :frown:

 

[sandmanwake]

Originally posted by: chuckywang


A better hint would be to integrate by parts.

It's a good thing I'm not being paid to give hints then otherwise my services would suck.

 

[chuckywang]

Originally posted by: sandmanwake

Originally posted by: chuckywang


A better hint would be to integrate by parts.

It's a good thing I'm not being paid to give hints then otherwise my services would suck.

lol!