I could use some VERY basic C programing help.

[mcveigh]

I have taken a simple C (not C++) class before. now for a new class I have a really simple first program, almost heloo world simple.
I have to take a 5 digit input number then add it to gether that's it.
EX: 12345 is the input the output would be 1+2+3+4+5=15

I originally wrote a program that did that but I thought the input was 5 separate integers, pressing enter after each one.
how can I read a string as separate integers? I'm thinking using getchar() is that right or am I way off?

here's what i wrote so far


#include <stdio.h>

int main()
{

int a,b,c, sum = 0;
printf("\nPlease enter three integers to be added together.\n");

scanf ("%d",&a);

scanf ("%d",&b);

scanf ("%d",&c);

sum = a + b + c;
printf("\n\n\nThe sum of your integers is %d\n", sum);
return 0;
}

 

[igowerf]

You could input the entire integer and then mod by powers of 10 to get each individual integer. As you get each integer, you can add it to the sum.

 

[Barnaby W. Füi]

int sum, i = 0;

printf("\nPlease enter three integers to be added together.\n");

for(i=0; i<5; i++)
sum += getchar();

printf("\n\n\nThe sum of your integers is %d\n", sum);
return 0;

------

It's been ages since I've touched C though (and when I did, it wasn't much more complex than this)

(I think getchar needs string.h)

 

[mcveigh]

Thanks everyone! I used your idea igowerf, as I recalled the instructor seemed to be stressing modulus functions in class.
(at the time I was surfing ATOT 😉....sometimes internet access in class can be a bad thing.)


#include <stdio.h>
//begin main function
int main()
{
//setup space for the whole integer, it's parts and the sum

int a,b,c,d, sum;
printf("\nPlease enter three integers to be added together.\n");
//gather input
scanf ("%d",&a);
//echo input to confirm
printf("\nYour three digit number was %d\n", a);
//get the last integer by using modulus 10
d = a % 10;
//get second integer by modulus 100 then subtracting the last digit and diving by 10
c = ((a % 100) - d) /10;
//get the first integer by diving by 100 as I am using integers and not floating numbers
b = a / 100;
//add all the parts up
sum = b + c + d;
//output to screen
printf("\nThe sum of your integers is:\n%d + %d + %d = %d\n", b,c,d,sum);
//return from function
return 0;
}