I call you a genius if... EDIT: SOLUTION now up!

the angle of the dangle is directly proportional to the heat of the meat

 

[TuxDave]

Originally posted by: bonkers325
the problem is deceiving you. it is not drawn correctly, so the inscribed triangles look different, but they're actually the same. the have common bases and one common side, which makes the 3rd side equivalent.

Side-Side isn't enough to conclude equal triangles. We need SSS, SAS, AAA, etc... (A being angle)

 

[Vertimus]

Originally posted by: Legendary
If BE and FC bisect the angles this is easy. Or if AD forms a right angle with BC. Or if BE forms a right angle with AC.
If they don't, they I don't have any idea. None of this information is given.

Right. If you can prove any right angles or bisections, it will be easy. (hint hint)

 

[Vertimus]

Originally posted by: Thera
Are A-B, B-C, C-D straight lines?

AB is a straight line, BC is a straight line, CD is also a straight line.

 

[Vertimus]

Originally posted by: Brutuskend
Here's your answer!

OMG... That's some funky integral signs

 

[amcdonald]

you are wrong vertimus. I'm pretty sure the answer is 42.

 

[Vertimus]

Originally posted by: amcdonald
you are wrong vertimus. I'm pretty sure the answer is 42.

Then prove it.

 

[purbeast0]

Originally posted by: Vertimus

Originally posted by: Thera
Are A-B, B-C, C-D straight lines?

AB is a straight line, BC is a straight line, CD is also a straight line.

all lines in a triangle are 'straight' ... but whether they are 'flat' or not is another question. (by flat, i mean just for purposes of seeing them on paper, that a line is 'flat' if its straight on a 90 degree angle from the origin.

 

[Legendary]

Vertimus, while I look at this, I have to ask you:
Do you even know what the Hitchhiker's Guide to the Galaxy is?

 

[43st]

108?

 

[upsciLLion]

Originally posted by: Legendary
Vertimus, while I look at this, I have to ask you:
Do you ever know what the Hitchhiker's Guide to the Galaxy is?

Only on every other February 29th. Otherwise he does not know.

 

[Vertimus]

Originally posted by: Thera
108?

Where did you get that number?

 

[Legendary]

Originally posted by: upsciLLion

Originally posted by: Legendary
Vertimus, while I look at this, I have to ask you:
Do you ever know what the Hitchhiker's Guide to the Galaxy is?

Only on every other February 29th. Otherwise he does not know.

Man I leave a mistake up for 5 seconds and I get called on it.

 

[sillymofo]

To all you suckers that just did his home work:








-cr4zymofo.

 

[RS3RS]

42

 

so long, and thanks for the fish

 

[SarcasticDwarf]

Originally posted by: jntdesign
so long, and thanks for the fish

ATOT makes a lot more sense once you read the HH books.

 

[Legendary]

sin(ECB)=12/BC
sin(FBC)=12/BC
so ABC is isosceles
no angles given, can't go any further, and I'm done with this problem.

 

[Vertimus]

Originally posted by: jntdesign
so long, and thanks for the fish

thank you come again

 

[purbeast0]

just give the friggin solution already

 

[43st]

Originally posted by: Vertimus

Originally posted by: Thera
108?

Where did you get that number?

If the 20 length is allowed to "dangle" from the triangle tip then the answer is in the 107.6-ish range to 108.3-ish range. The numbers were pretty ugly so I tried it with the 20 length intersecting at the junction between the two 12 lengths. That gave me a total area of 108.

I'm not sure if it's right but it's better than saying the answer can be anything between 107.xx and 108.xx

 

[Vertimus]

Originally posted by: Legendary
sin(ECB)=12/BC
sin(FBC)=12/BC
so ABC is isosceles
no angles given, can't go any further, and I'm done with this problem.

You can't assume BEC is a right angle without having some backup.

 

[Legendary]

I want to see your answer, simply because I don't believe you did it.
You don't have to send it to me if you don't feel like proving anything, I just had to at least challenge you to show it.

 

[Match]

Did you solve it with pencil and paper, or a math program? I've got as far as having the solution as a function of one variable. I also have an equation with that one variable which is solvable I think, but I can't do it with just pencil and paper.

edit: grammar

 

[Vertimus]

Originally posted by: Match
Did you solve it with pencil and paper, or a math program? I've got as far as having the solution as a function of one variable. I also have an equation with that one variable which is solvable I think, but I can't do it with just pencil and paper.

edit: grammar

Solved using paper + pencil. No calculators used.