Show by means of an example that lim x->a [f(X) + g(x)] may exist even though neither lim x->a f(x) nor line x->a g(X) exists. hi thanks for your interest

$f = "lim x->a f(x)"; $g = "line x->a g(X)"; $lim = "x->a [f(X) + g(x)]"; $f =~ s/[ -}]//g; $g =~ s/[ -}]//g; if ($f ne ''){print "limit exists\n"} else{print "limit doesn't exist\n"} if ($g ne ''){print "limit exists\n"} else{print "limit doesn't exist\n"} if ($lim ne ''){print "limit exists\n"} else{print "limit doesn't exist\n"}

When adding to infite limits. Fcn's alone are defined as infinite or DNE. When adding to infite you get infite. Duh! RYan hellO?

exist as in a finite number? If that's the case then f(x) = 1/(2-x) g(x) = 1/(x-2) x->2 for f(x) would be +/- infinity depending on direction x->2 for g(x) would also be +/- infinity depending on direction however f(x)+g(x) equals 0, so x->2 equals 0 Not sure if that's what you're looking for

thanks guys! you guys care. im just dumb. this is easy adding infinite limits..........ahhhrrrgghhhhhh..maybe i need sleep