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How would you simplify "(3n-2)!"?

What do you mean by simplify.??? Do you want a closed form for this expression? Also the expression is not valid for base case n= 0.I am trying to figure out what you want as I like factroial and closed forms.
 
Originally posted by: eigen
What do you mean by simplify.??? Do you want a closed form for this expression? Also the expression is not valid for base case n= 0.I am trying to figure out what you want as I like factroial and closed forms.

I'm not really sure...a friend (studying statistics) just IM'd me asking if I knew how to simplify the factorial. I tried to help but I'm not even sure myself. I thought it would be some kind of series or sequence related.
 
(3*n)! / (3 * n * (3 * n - 1)) is the answer my TI-89 gives me, but I have no idea where that comes from.
 
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.
 
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with the correct math.

Um yes (3n-2)! does = (3n-2)(3n-1)(3n)!


Hmm, it doesn't....but (n+1)! = (n+1)n!
 
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.


Heh..i thought they were (3n+2)! 😱


 
Originally posted by: JohnCU
Um yes (3n-2)! does = (3n-2)(3n-1)(3n)!

Bullsh!t

n=1

(3n-2)! = (3*1-2)! = 1! = 1

(3n-2)(3n-1)(3n)! = (3*1-2)(3*1-1)(3*1)! = 1*2*6 = 12

Copnsidered NOT proven. 😉
 
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.


Heh..i thought they were (3n+2)! 😱

Way to go guys, now you've got him really confused.
 
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