How would you simplify "(3n-2)!"?

eigen

Diamond Member
Nov 19, 2003
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What do you mean by simplify.??? Do you want a closed form for this expression? Also the expression is not valid for base case n= 0.I am trying to figure out what you want as I like factroial and closed forms.
 

CrackaLackaZe

Senior member
Jun 29, 2002
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Originally posted by: eigen
What do you mean by simplify.??? Do you want a closed form for this expression? Also the expression is not valid for base case n= 0.I am trying to figure out what you want as I like factroial and closed forms.

I'm not really sure...a friend (studying statistics) just IM'd me asking if I knew how to simplify the factorial. I tried to help but I'm not even sure myself. I thought it would be some kind of series or sequence related.
 

KevinF

Senior member
Aug 25, 2000
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(3*n)! / (3 * n * (3 * n - 1)) is the answer my TI-89 gives me, but I have no idea where that comes from.
 

CrackaLackaZe

Senior member
Jun 29, 2002
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Originally posted by: Gibson486
i will give you a hint.....start plugging in numbers from 0 to whenever....

So just go from n=0 to n=5, look for a pattern, and put down a series for it?
 

Kyteland

Diamond Member
Dec 30, 2002
5,747
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Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)!
= (3n-2)!*(3-1)/(3n-1)
= (3n-1)!/(3n-1)
= (3n-1)!*(3n)/(3n-3)/(3n)
= (3n)!/(3n-1)/(3n)
 

Kyteland

Diamond Member
Dec 30, 2002
5,747
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Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.
 

JohnCU

Banned
Dec 9, 2000
16,528
4
0
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with the correct math.

Um yes (3n-2)! does = (3n-2)(3n-1)(3n)!


Hmm, it doesn't....but (n+1)! = (n+1)n!
 

Crusty

Lifer
Sep 30, 2001
12,684
2
81
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.


Heh..i thought they were (3n+2)! :eek:


 

Kyteland

Diamond Member
Dec 30, 2002
5,747
1
81
Originally posted by: JohnCU
Um yes (3n-2)! does = (3n-2)(3n-1)(3n)!

Bullsh!t

n=1

(3n-2)! = (3*1-2)! = 1! = 1

(3n-2)(3n-1)(3n)! = (3*1-2)(3*1-1)(3*1)! = 1*2*6 = 12

Copnsidered NOT proven. ;)
 

NYSTrooper

Banned
Mar 22, 2004
169
0
0
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
Originally posted by: Kyteland
Originally posted by: MCrusty
(3n-2)(3n-1)(3n)!

Um, no.

(3n-2)! = (3n)!/((3n)(3n-1))

Uhmm...wtf are you talking about...

What you put up above is not equal to (3n-2)!

(3n-2)! != (3n-2)(3n-1)(3n)!

(3n-2)! = (3n)!/((3n)(3n-1))

edit: I edited my post with better math.


Heh..i thought they were (3n+2)! :eek:

Way to go guys, now you've got him really confused.