Goosemaster
Lifer
Originally posted by: Howard
How is (lnu)du/u = udu?Originally posted by: Goosemaster
[e^(2u)]/u - int[(lnu)/u] = int(udu)?
no
1)e^(2u)]/u - int[(lnu)/u]
2)e^(2u)]/u - int(udu)
I lhate writing sh!t over an over again so I jsut keep goign only with what needs work
You used u = (lnu)/u?
Man, I am so going to fail.
no. for this explanation assume that u=x , as it is.
int ( 1/x * ln(x) )
substitute:
same thing as int (u du) where u=lnx and du=1/x
then int (udu) = (u^2)/2
int ( u du )