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How much of an inverse impact is the earth rotation on gravity?

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syberscott

Senior member
Feb 20, 2003
372
0
0
Originally posted by: Iron Woode
Originally posted by: edro13
Originally posted by: Beau
Originally posted by: edro13
Well no crap... I was using it as an example....
An example of what? I don't see how it applies.

There is gravity on the moon, but it is a lot less.... yet you do not fly off the moon when there is no rotation.... Therefore, the centrifigal force is prolly a lot less than gravity.
The moon rotates on its axis. This is basic astronomy.
Actually the moon doesn't really rotate. The Earth's gravity has captured it, so the moon always shows us the same face.
 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,299
12,818
136
Originally posted by: syberscott
Originally posted by: Iron Woode
Originally posted by: edro13
Originally posted by: Beau
Originally posted by: edro13
Well no crap... I was using it as an example....
An example of what? I don't see how it applies.

There is gravity on the moon, but it is a lot less.... yet you do not fly off the moon when there is no rotation.... Therefore, the centrifigal force is prolly a lot less than gravity.
The moon rotates on its axis. This is basic astronomy.
Actually the moon doesn't really rotate. The Earth's gravity has captured it, so the moon always shows us the same face.
The moon rotates every 30 days. Check it out.

Quote:

The asymmetric nature of this gravitational interaction is also responsible for the fact that the Moon rotates synchronously, i.e. it is locked in phase with its orbit so that the same side is always facing toward the Earth. Just as the Earth's rotation is now being slowed by the Moon's influence so in the distant past the Moon's rotation was slowed by the action of the Earth, but in that case the effect was much stronger. When the Moon's rotation rate was slowed to match its orbital period (such that the bulge always faced toward the Earth) there was no longer an off-center torque on the Moon and a stable situation was achieved. The same thing has happened to most of the other satellites in the solar system. Eventually, the Earth's rotation will be slowed to match the Moon's period, too, as is the case with Pluto and Charon.

Taken from: http://seds.lpl.arizona.edu/nineplanets/nineplanets/luna.html

There is a link in the word synchronously that explains how this word is defined.
 

Beau

Lifer
Jun 25, 2001
17,730
0
76
www.beauscott.com
Originally posted by: Iron Woode
Originally posted by: Beau
Originally posted by: Iron Woode


You can't even spell, let alone understand basic physics.

Ok I will make this simple:

Gravity is not caused by a rotating body. Gravity is a curvature of the space-time continuim caused by the mass of an object. Gravity acts equally at all parts of the globe, drawing objects to the earth's center at a constant rate of acceleration. Whether the object weighs an ounce or 10 tonnes or if you have 2 different weighted objects, they all accelerate at the same rate to the ground.

Inertia is the tendancy of an object to continue doing what it is doing. In other words if an object is still, then it will stay still until some force acts upon it.

Just what are you trying to get at? The earth's rotation is caused by its formation. The rate of rotation is slowing down, not due to gravity, but, due to the drag of our atmosphere and the tug of our moon. In the past a day may have been 16 hoursllong and one day the earth will just stop rotating.

I didn't say gravity was caused by a rotating body. I know what gravity is.

Re-read the first post. I may have gotten my terms wrong, but the idea is still there. I'm simply wondering how much of an opposing force the earth rotation plays to gravity. Gravity being the force created by earth's mass, causing other objects to fall to it's center. The earths rotation (without gravity) would be cause objects to fly off the surface, so it must act as an anti-gravity force to a certain degree. If it does, then wouldn't it play more of an opposing force to gravity at the earths equator than at the poles?
I think what you are asking is :

Can the rotational force of the earth have a cancelling effect on gravity at different places on the earth?

Is this correct?

yes.

I found what I was looking for
 

Iron Woode

Elite Member
Super Moderator
Oct 10, 1999
31,299
12,818
136
Originally posted by: Beau
Originally posted by: Iron Woode
Originally posted by: Beau
Originally posted by: Iron Woode


You can't even spell, let alone understand basic physics.

Ok I will make this simple:

Gravity is not caused by a rotating body. Gravity is a curvature of the space-time continuim caused by the mass of an object. Gravity acts equally at all parts of the globe, drawing objects to the earth's center at a constant rate of acceleration. Whether the object weighs an ounce or 10 tonnes or if you have 2 different weighted objects, they all accelerate at the same rate to the ground.

Inertia is the tendancy of an object to continue doing what it is doing. In other words if an object is still, then it will stay still until some force acts upon it.

Just what are you trying to get at? The earth's rotation is caused by its formation. The rate of rotation is slowing down, not due to gravity, but, due to the drag of our atmosphere and the tug of our moon. In the past a day may have been 16 hoursllong and one day the earth will just stop rotating.

I didn't say gravity was caused by a rotating body. I know what gravity is.

Re-read the first post. I may have gotten my terms wrong, but the idea is still there. I'm simply wondering how much of an opposing force the earth rotation plays to gravity. Gravity being the force created by earth's mass, causing other objects to fall to it's center. The earths rotation (without gravity) would be cause objects to fly off the surface, so it must act as an anti-gravity force to a certain degree. If it does, then wouldn't it play more of an opposing force to gravity at the earths equator than at the poles?
I think what you are asking is :

Can the rotational force of the earth have a cancelling effect on gravity at different places on the earth?

Is this correct?

yes.

I found what I was looking for
I was confused with your posts because there was too much scientific jargon being used. A simpler question, like the one i just asked, would have been a better choice. :)

But I understand that the chilli is affecting you. ;)
 

Beau

Lifer
Jun 25, 2001
17,730
0
76
www.beauscott.com
Originally posted by: Iron Woode
Originally posted by: Beau
Originally posted by: Iron Woode
Originally posted by: Beau
Originally posted by: Iron Woode


You can't even spell, let alone understand basic physics.

Ok I will make this simple:

Gravity is not caused by a rotating body. Gravity is a curvature of the space-time continuim caused by the mass of an object. Gravity acts equally at all parts of the globe, drawing objects to the earth's center at a constant rate of acceleration. Whether the object weighs an ounce or 10 tonnes or if you have 2 different weighted objects, they all accelerate at the same rate to the ground.

Inertia is the tendancy of an object to continue doing what it is doing. In other words if an object is still, then it will stay still until some force acts upon it.

Just what are you trying to get at? The earth's rotation is caused by its formation. The rate of rotation is slowing down, not due to gravity, but, due to the drag of our atmosphere and the tug of our moon. In the past a day may have been 16 hoursllong and one day the earth will just stop rotating.

I didn't say gravity was caused by a rotating body. I know what gravity is.

Re-read the first post. I may have gotten my terms wrong, but the idea is still there. I'm simply wondering how much of an opposing force the earth rotation plays to gravity. Gravity being the force created by earth's mass, causing other objects to fall to it's center. The earths rotation (without gravity) would be cause objects to fly off the surface, so it must act as an anti-gravity force to a certain degree. If it does, then wouldn't it play more of an opposing force to gravity at the earths equator than at the poles?
I think what you are asking is :

Can the rotational force of the earth have a cancelling effect on gravity at different places on the earth?

Is this correct?

yes.

I found what I was looking for
I was confused with your posts because there was too much scientific jargon being used. A simpler question, like the one i just asked, would have been a better choice. :)

But I understand that the chilli is affecting you. ;)

Speaking of which... I need to go get a fan....
 

Eli

Super Moderator | Elite Member
Oct 9, 1999
50,419
8
81
Originally posted by: Iron Woode
Originally posted by: syberscott
Originally posted by: Iron Woode
Originally posted by: edro13
Originally posted by: Beau
Originally posted by: edro13
Well no crap... I was using it as an example....
An example of what? I don't see how it applies.

There is gravity on the moon, but it is a lot less.... yet you do not fly off the moon when there is no rotation.... Therefore, the centrifigal force is prolly a lot less than gravity.
The moon rotates on its axis. This is basic astronomy.
Actually the moon doesn't really rotate. The Earth's gravity has captured it, so the moon always shows us the same face.
The moon rotates every 30 days. Check it out.

Quote:

The asymmetric nature of this gravitational interaction is also responsible for the fact that the Moon rotates synchronously, i.e. it is locked in phase with its orbit so that the same side is always facing toward the Earth. Just as the Earth's rotation is now being slowed by the Moon's influence so in the distant past the Moon's rotation was slowed by the action of the Earth, but in that case the effect was much stronger. When the Moon's rotation rate was slowed to match its orbital period (such that the bulge always faced toward the Earth) there was no longer an off-center torque on the Moon and a stable situation was achieved. The same thing has happened to most of the other satellites in the solar system. Eventually, the Earth's rotation will be slowed to match the Moon's period, too, as is the case with Pluto and Charon.

Taken from: http://seds.lpl.arizona.edu/nineplanets/nineplanets/luna.html

There is a link in the word synchronously that explains how this word is defined.
The Earth's rotation carries the Earth's bulges slightly ahead of the point directly beneath the Moon. This means that the force between the Earth and the Moon is not exactly along the line between their centers producing a torque on the Earth and an accelerating force on the Moon. This causes a net transfer of rotational energy from the Earth to the Moon, slowing down the Earth's rotation by about 1.5 milliseconds/century and raising the Moon into a higher orbit by about 3.8 centimeters per year.

Whoa.. That's crazy sh!t. Astronomy is cool. :cool:

 

Heisenberg

Lifer
Dec 21, 2001
10,621
1
0
Originally posted by: Eli
Originally posted by: Mday
WTF

http://www.syvum.com/physics/gravitation/gravitation2.html

they call Fc, centrifugal force. THEY ARE STUPID. centrifugal force is NOT a real phenomenon. </physics>

anyway, the effects of the rotation of the earth on gravity is MINIMAL. and relative to the earth, you're not moving.
????

I know nothing of physics, but the centrifugal clutch in my chainsaw disagrees. :p
He's right, mainly. Centrifugal force is what's called a pseudo-force. It results from centripetal force, and is because of a non-inertial reference frame.