mygumballs
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- Sep 21, 2001
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Originally posted by: Syringer
Originally posted by: b0mbrman
By measuring using bigger and bigger circles
Actually, one real way that I remember is 4 - 4/3 + 4/5 - 4/7 + 4/9...
That's cool. I just tried summing up 100 terms using that on my TI-89, and got 3.13159.
1000 terms gets me 3.14059. Anything bigger takes way too long..
The simplification of the arctan series. It's actually exactly pi, when fully evaluated. Unfortunately, it is also terribly inefficient as far as a series is concerned.Originally posted by: Syringer
Originally posted by: b0mbrman
By measuring using bigger and bigger circles
Actually, one real way that I remember is 4 - 4/3 + 4/5 - 4/7 + 4/9...
That's cool. I just tried summing up 100 terms using that on my TI-89, and got 3.13159.
1000 terms gets me 3.14059. Anything bigger takes way too long..
Interesting, please tell more. Do you have a link?Originally posted by: mygumballs
the more points your generate, the better the approximatio.
I'm too lazy to read the thread.Originally posted by: Goosemaster
22/7...if you are lazy...![]()
Originally posted by: dullard
Interesting, please tell more. Do you have a link?Originally posted by: mygumballs
the more points your generate, the better the approximatio.
Originally posted by: Kyteland
355/113Originally posted by: nakedfrog
22/7
Originally posted by: Goosemaster
22/7...if you are lazy...![]()
Originally posted by: dullard
There are dozens and dozens of ways. Here is a fun method. It is quite powerful at calculating all types of things, but it is slow and inefficient.
3's good enough for my lazy ass...Originally posted by: nakedfrog
Originally posted by: Kyteland
355/113Originally posted by: nakedfrog
22/7
See this post:
Originally posted by: Goosemaster
22/7...if you are lazy...![]()
And I am, so there![]()
Originally posted by: dullard
Interesting, please tell more. Do you have a link?Originally posted by: mygumballs
the more points your generate, the better the approximatio.
Time to replace your sarcasm and repost meters. Both are malfunctioning today. I posted that exact solution already in this thread.Originally posted by: mygumballs
no, a friend of mine just told me about it. but a sort of proof is easy. the ratio of points in teh square to the points in the circle is the same as the ratio of the area of the circle to the area of the square. if the square's sides are x long, then its area is x^2 and the area of the circle is 1/4 pi x^2. therefore the ratio is 1/4 pi.
Originally posted by: oboeguy
Originally posted by: dullard
There are dozens and dozens of ways. Here is a fun method. It is quite powerful at calculating all types of things, but it is slow and inefficient.
Dang you for beating me to the Monte Carlo simulation method.
And to all the morons who didn't understand the OP... PWNED! It was pretty obvious the OP was asking how to compute "pi", not what it is.![]()