How do you do this math problem?

ArmenK

Golden Member
Oct 16, 2000
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log (x-1) = log (x-2) - log (x+2)
log (x-1) = log[ (x-2)/(x+2) ]
x-1 = (x-2)/(x+2)

solve
 

ArmenK

Golden Member
Oct 16, 2000
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Originally posted by: gnuel3
Oh yeah! The logs cancel..forgot that...heh


Thanks alot! :D

the logs dont cancel, you do e^ to both sides

for example, you couldnt cancel the logs from log (x-1) = log (x-2) - log (x+2) directly
 

Dissipate

Diamond Member
Jan 17, 2004
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Originally posted by: ArmenK
Originally posted by: gnuel3
Oh yeah! The logs cancel..forgot that...heh


Thanks alot! :D

the logs dont cancel, you do e^ to both sides

for example, you couldnt cancel the logs from log (x-1) = log (x-2) - log (x+2) directly

No, e is only if it is natural log or ln. He is talking about log and furthermore he never indicated the base of the log. I assume it is base 10.
 

ArmenK

Golden Member
Oct 16, 2000
1,600
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Originally posted by: Dissipate
Originally posted by: ArmenK
Originally posted by: gnuel3
Oh yeah! The logs cancel..forgot that...heh


Thanks alot! :D

the logs dont cancel, you do e^ to both sides

for example, you couldnt cancel the logs from log (x-1) = log (x-2) - log (x+2) directly

No, e is only if it is natural log or ln. He is talking about log and furthermore he never indicated the base of the log. I assume it is base 10.

When you get to college, log = ln
 

Dissipate

Diamond Member
Jan 17, 2004
6,815
0
0
Originally posted by: ArmenK
Originally posted by: Dissipate
Originally posted by: ArmenK
Originally posted by: gnuel3
Oh yeah! The logs cancel..forgot that...heh


Thanks alot! :D

the logs dont cancel, you do e^ to both sides

for example, you couldnt cancel the logs from log (x-1) = log (x-2) - log (x+2) directly

No, e is only if it is natural log or ln. He is talking about log and furthermore he never indicated the base of the log. I assume it is base 10.

When you get to college, log = ln

Huh? Not in my college. 99% of the time I don't mess with log bases other than e but I have never seen a problem where ln == log.