- Dec 7, 2001
- 10
- 0
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My first year physics text says that F= -kx only works for small displacements. And I didn't want to post on sci.physics, which is a real mess. So, does anyone know how exactly to relate force and displacement for springs? I would imagine it involves the stress and strain characteristics of the substance somehow...
It doesn't seem similar to pendulum, where the accepted approximation is torque = -mgL sin (theta) = -mgL (theta) for small theta.
It doesn't seem similar to pendulum, where the accepted approximation is torque = -mgL sin (theta) = -mgL (theta) for small theta.