Mmmmm, I like that hot dog experiment. I can microwave 2 Ball Parks in 2 minutes @ 50% power, and it sounds like I could do a very large number using the "wall socket" method in less time, as long as I don't blow a fuse. Hmmm, I know what I'm doing at the next BBQ.....BTW, how evenly do the Hot Dogs cook?
Anyhow, it's been while since I looked @ circuit problems, but I'm feeling like reliving my past so lets see:
For the initial case, we have resistors in parallel, so that means:
R=Hot Dog Resistance
V=Voltage potential (120V if in a wall socket)
I=Current in the dog
N=number of dogs
So, the overall Parallel Dog resistance will depend on the # of dogs, and the total resistance is:
1/R(total) = 1/R + 1/R + ...... for the number of dogs = N/R
1/R(total) = N/R
R(total) = R/N
The Series dog resistance is:
R(total) = R + R + R..... = N*R
R(total) = N*R
So, if V=IR(total) and Power = VI = (I^2)R(total)
Then I = V/R(total) and P = (V/R(total))^2(R(total)) = (V^2)/R(total)
So:
P(parallel) = N(V^2)/R
P(series) = (V^2)/RN
So:
P(parallel) = (N^2)P(series)
So, this means that the time it takes will grow exponentially (or is it geometrically) with the number of dogs. Since I don't know how many dogs were cooking in the original case, I can't say for sure how long it will take, but if you cooked 2 dogs in 1.5 minutes in parallel, it would take 4X as long to cook 2 dogs in series (and 16X as long if you cooked 4 dogs). Also, as you add more dogs to the parallel circuit, the overall resistance goes down and you can actually cook them faster (until you blow a fuse, anyway). Seems kinda conuter-intuitive.
I'm sure I screwed up somewhere, so hopefully I don't get banned from this forum, hehe.
Man, I can't believe I just did that, and now I'm nervous about looking too dorky if I post it all.
I need to go rest now....
-D'oh!