Help with Math (Area) Problem

[SkdMrkLcy]

This is for an area thing my boss is working on and I am at a complete loss and can not remember how to do this or if I even have enough info, as everything I know requires at least one angel.

Here it is Pic

Any help would be great.

Thanks

Another pic for actuall scale PIC2

 

[BigJ]

Do you have angle measurements? If so it should be relatively easy to compute using a few laws.

EDIT: Damn, just read you don't have any.

 

[SkdMrkLcy]

Yeah that is the issue, and it has been about 3 years since I was in a calc/trig class.

I am thinking it is not possible at least with this information.

 

[PowerMac4Ever]

Anything is possible if you put your mind to it.

 

[TuxDave]

Originally posted by: PowerMac4Ever
Anything is possible if you put your mind to it.

It depends if there is only one shape that can have 6 sides with those lengths. If not, then it is impossible. Are you given that any sides are parallel to each other? If all opposite sides are parallel, then I think it's solvable.

 

[notfred]

It's four triangles.

Finding the area of triangles is easy.

 

[TuxDave]

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

If I drew you a 4-sided polygon with each side having a length of 1, it's technically 2 triangles but it's not enough information to get a deterministic area. (square, diamond, etc...)

 

[BigJ]

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

 

[silverpig]

Originally posted by: TuxDave

Originally posted by: PowerMac4Ever
Anything is possible if you put your mind to it.

It depends if there is only one shape that can have 6 sides with those lengths. If not, then it is impossible. Are you given that any sides are parallel to each other? If all opposite sides are parallel, then I think it's solvable.

Whether or not the sides are parallel depends on the lengths of the sides I'd imagine... especially if the shape is unique.

I thought of doing the triangles and using a combination of sine law, cosine law, angle addition etc, but still...

 

[TuxDave]

I am 100% sure that this is unsolvable without anymore information.

 

[SkdMrkLcy]

TO find the area of a triangle you have to have at least one angle. at least as far as I know. or the hieight to turn it into several right triangles.

 

[silverpig]

As I thought... depends on the angles.

 

[TuxDave]

Originally posted by: silverpig

Originally posted by: TuxDave

Originally posted by: PowerMac4Ever
Anything is possible if you put your mind to it.

It depends if there is only one shape that can have 6 sides with those lengths. If not, then it is impossible. Are you given that any sides are parallel to each other? If all opposite sides are parallel, then I think it's solvable.

Whether or not the sides are parallel depends on the lengths of the sides I'd imagine... especially if the shape is unique.

I thought of doing the triangles and using a combination of sine law, cosine law, angle addition etc, but still...

Well, I'm doing some visual manipulation on my behalf. If you set the angle between 302 and 225 and force 57 and 80 to be parallel, then you have one shape. Now if you pivot 80 inwards, you'll see the point between 196 and 350 start moving up and right. So you have multiple shapes with the same sides and different angles.

 

[notfred]

Originally posted by: BigJ

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

Ever hear of a protractor, or a ruler? lengths and angles can be measured.

 

[PowerMac4Ever]

Originally posted by: TuxDave

Originally posted by: PowerMac4Ever
Anything is possible if you put your mind to it.

It depends if there is only one shape that can have 6 sides with those lengths. If not, then it is impossible. Are you given that any sides are parallel to each other? If all opposite sides are parallel, then I think it's solvable.

How am I supposed to know???

 

[DingDingDao]

Originally posted by: TuxDave
I am 100% sure that this is unsolvable without anymore information.

Winner. You can't do trig without at least one angle given, or knowing the value of all three sides.

 

[BigJ]

Originally posted by: notfred

Originally posted by: BigJ

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

Ever hear of a protractor, or a ruler? lengths and angles can be measured.

Did you bother reading the OP? This diagram is hardly drawn to scale. And unless you have a giant protractor and ruler to go to his job site and measure this, I suggest you find me another way to do it without angles.

 

[TuxDave]

Originally posted by: PowerMac4Ever

Originally posted by: TuxDave

Originally posted by: PowerMac4Ever
Anything is possible if you put your mind to it.

It depends if there is only one shape that can have 6 sides with those lengths. If not, then it is impossible. Are you given that any sides are parallel to each other? If all opposite sides are parallel, then I think it's solvable.

How am I supposed to know???

First two sentences were for you. Next two were for the OP. My bad.

 

[mchammer187]

Originally posted by: notfred

Originally posted by: BigJ

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

Ever hear of a protractor, or a ruler? lengths and angles can be measured.

look at the pic it is obviously not drawn to scale

 

[notfred]

Originally posted by: BigJ

Originally posted by: notfred

Originally posted by: BigJ

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

Ever hear of a protractor, or a ruler? lengths and angles can be measured.

Did you bother reading the OP? This diagram is hardly drawn to scale. And unless you have a giant protractor and ruler to go to his job site and measure this, I suggest you give me another way to do it without angles.

The idea that someone is actually going to build something in this space but has no capacity to measure the space is ridiculous. This is why people called "surveyors" exist. Afterall, someone came up with the dimensions we're given, right? Send him back out to take 3 more measurements.

 

[mchammer187]

Originally posted by: notfred

Originally posted by: BigJ

Originally posted by: notfred

Originally posted by: BigJ

Originally posted by: notfred
It's four triangles.

Finding the area of triangles is easy.

How are you going to find the area without angles?

Ever hear of a protractor, or a ruler? lengths and angles can be measured.

Did you bother reading the OP? This diagram is hardly drawn to scale. And unless you have a giant protractor and ruler to go to his job site and measure this, I suggest you give me another way to do it without angles.

The idea that someone is actually going to build something in this space but has no capacity to measure the space is ridiculous. This is why people called "surveyors" exist. Afterall, someone came up with the dimensions we're given, right? Send him back out to take 3 more measurements.

hence it is impossible to determine the area with the information given

 

[Kyteland]

Originally posted by: notfred
The idea that someone is actually going to build something in this space but has no capacity to measure the space is ridiculous. This is why people called "surveyors" exist. Afterall, someone came up with the dimensions we're given, right? Send him back out to take 3 more measurements.

And if they can't get to the site to do more mesurements they can probably download satalite images of the plot from the web and take angle mesurements from that.

 

[JonnyStarks]

scale it down? make the measurements in millimetres, then the longest side is 35 centimetres.... thenyou could get a rough estimate?

 

[SkdMrkLcy]

Yeah he did not get all the info he needed and none of them are parellel.

Thanks for the info though guys.

 

[SkdMrkLcy]

I got another image from a website.

Turns out no one has ever survayed the area due to the hills and woods, and he is trying to apprise it and just needs a good estimate. I am going to try with the scale pic I put up to find out some more. THought I would post just incase I come up empty.

PIC2