Help with Logarithms

[GambiT]

I have an algorithms class and they're bringing in logarithms. I can't remember how to solve for them. I've gotten a couple of books on Algebra II but I'm not getting it.

Looking to solve for n:
8n^2 = 64n Log n

The Log is base 2. Any help is appreciated.

 

[DarkForceRising]

divide through by 64n. raise everything to an exponent of 2. so 2^(8n^2/64n) = 2^(log n) = n.

I believe that's correct. For instance, e^(ln x) = x.

 

[esun]

Generally, when solving a logarithmic equation with a linear term (i.e. the equation contains x and log(x)), if you can re-arrange the formula to get something in the form of x = A * log(x), where A is some constant, you can solve the problem via iteration. Iteration means you plug in a guess to the right side of the equation (containing log(x)), then compute a new value for x. Repeat until the solution converges to a particular accuracy.

 

[Apathetic]

Since this is probably a computer science class you're taking, just remember that the instructor is probably talking about log base 2 and not base 10.

Dave

 

[jman19]

Originally posted by: Apathetic
Since this is probably a computer science class you're taking, just remember that the instructor is probably talking about log base 2 and not base 10.

Dave

Um, he said that in the OP 😕