Originally posted by: Heisenberg
The head would travel farther. It's a simple arc length problem.
Originally posted by: bleeb
Originally posted by: Heisenberg
The head would travel farther. It's a simple arc length problem.
I think this guy is trying to trick us into solving his homework problem for him.
I'm not answering that part. You'll just have to figure it out on your own if you want the bonus points. 😛Originally posted by: PHiuR
the question also states How much Further? not just which travels more...
Originally posted by: Heisenberg
I'm not answering that part. You'll just have to figure it out on your own if you want the bonus points. 😛Originally posted by: PHiuR
the question also states How much Further? not just which travels more...
Originally posted by: dave127
easy...his feet travel the circumference of the earth at the equator...im sure you dont need an exact answer, because its really not possible to calculate...what you do is take the radius of the earth at the equator and use it in the equation for the circumference, then you do the same for his head, but add six feet to the radius at the equator, find the difference between the two answers, and voila!!!
Dave
Originally posted by: PHiuR
Originally posted by: dave127
easy...his feet travel the circumference of the earth at the equator...im sure you dont need an exact answer, because its really not possible to calculate...what you do is take the radius of the earth at the equator and use it in the equation for the circumference, then you do the same for his head, but add six feet to the radius at the equator, find the difference between the two answers, and voila!!!
Dave
makes sense!...lemme try this one out...
Originally posted by: PHiuR
Originally posted by: dave127
easy...his feet travel the circumference of the earth at the equator...im sure you dont need an exact answer, because its really not possible to calculate...what you do is take the radius of the earth at the equator and use it in the equation for the circumference, then you do the same for his head, but add six feet to the radius at the equator, find the difference between the two answers, and voila!!!
Dave
makes sense!...lemme try this one out...
Originally posted by: TuxDave
Originally posted by: PHiuR
Originally posted by: dave127
easy...his feet travel the circumference of the earth at the equator...im sure you dont need an exact answer, because its really not possible to calculate...what you do is take the radius of the earth at the equator and use it in the equation for the circumference, then you do the same for his head, but add six feet to the radius at the equator, find the difference between the two answers, and voila!!!
Dave
makes sense!...lemme try this one out...
Doh... we're not supposed to help him with his hmwk. And yeah, you definitely do NOT need any more information to solve this.
Originally posted by: glugglug
You are all wrong. His feet travel farther because while his head goes almost in a straight line following the very slow curvature of the Earth, his feet are repeatedly going up and down, with sort of a rapid rotational motion superimposed on the linear motion component. Unless of course the guy is doing the moonwalk. But the problem clearly states he is on Earth.
Originally posted by: glugglug
You are all wrong. His feet travel farther because while his head goes almost in a straight line following the very slow curvature of the Earth, his feet are repeatedly going up and down, with sort of a rapid rotational motion superimposed on the linear motion component. Unless of course the guy is doing the moonwalk. But the problem clearly states he is on Earth.