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help me with HW and i'll show you bush!!!

O

Omegachi

Diamond Member
help me solve this problem, and i'll show you bush 😉

This is a physics problem on fluids:

A ship sails from seawater (specific gravity 1.025) into fresh water and therefore sinks slightly. When its load of 600,000kg is removed, it returns to its original level. Assuming that the sides of the ship are vertical at the water line, find the mass of the ship before it was unloaded.
 
physics 3? whats that? Its just college level physics, i am stuck on this problem 🙁

don't you guys wanna see bush?haha
 
Answer is 24600000 kg.

Here is how I did it:

m = mass of ship w/ cargo
A = area of ship's underside (sides are vertical)
h = height of water line relative to bottom of the ship
ds = density (specific gravity) of salt water
dw = density (specific gravity) of fresh water ( = 1)
g = gravity

ds*h*A*g = m*g

Cancel g-

ds*h*A = m

Consider ship in freshwater after it is unloaded-

dw*h*A = m - 600000

Solve for h-

h = m/(ds*A)

Substitute-

m*dw/ds = m - 600000

Solve for m.

PM me my bush.

Ryan
 


<< holy shiznit! is that physics 3? >>



Nope, physics one. It is just a simple force balance/buoyancy problem.

Ryan
 
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