- Nov 12, 2004
- 1,664
- 0
- 0
givens:
#1: z > y > x
#2: z + y + x = 200
#3: z - y = y - x
calculate z, y, and x:
z + x = 200 - y (from #2)
z + x = 2y (from #3)
2y = 200 - y
3y = 200
y = 66 2/3
z + x = 133 1/3
This is where I get stuck. Just by going through some numbers brute force, I calculate z = 100, y = 66 2/3, and x = 33 1/3. But I'd like to know how to actually solve for z and x.
#1: z > y > x
#2: z + y + x = 200
#3: z - y = y - x
calculate z, y, and x:
z + x = 200 - y (from #2)
z + x = 2y (from #3)
2y = 200 - y
3y = 200
y = 66 2/3
z + x = 133 1/3
This is where I get stuck. Just by going through some numbers brute force, I calculate z = 100, y = 66 2/3, and x = 33 1/3. But I'd like to know how to actually solve for z and x.