having trouble with a math problem

hellokeith

Golden Member
Nov 12, 2004
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givens:

#1: z > y > x

#2: z + y + x = 200

#3: z - y = y - x


calculate z, y, and x:

z + x = 200 - y (from #2)

z + x = 2y (from #3)

2y = 200 - y

3y = 200

y = 66 2/3

z + x = 133 1/3

This is where I get stuck. Just by going through some numbers brute force, I calculate z = 100, y = 66 2/3, and x = 33 1/3. But I'd like to know how to actually solve for z and x.
 

DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
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There isn't a unique solution for z and x.

Example: z = 100, x = 33 1/3
This satisfies #1, #2, #3

Example: z = 100 1/3, x = 33
This satisfies #1, #2, #3