Has it been proven that the antiderivative (indefinite integral) of sinx/x does not exist?

Aug 10, 2001
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One of my old calculus textbooks says that you can prove that the sinx/x doesn't have an antiderivative. But I have had teachers say that we just don't know how to take the antiderivative of sinx/x. Someone else told me that you can find the antiderivative by using complex variables (but he might have just been high on crack).
 
Aug 10, 2001
10,420
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Originally posted by: akubi
that's how it's done, SON.


ooooooooooooooh

Ok, but that just gives you a way to approximate the definite integral. It doesn't give you an antiderivative. And don't call me SON, son.
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
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Originally posted by: Random Variable
One of my old calculus textbooks says that you can prove that the sinx/x doesn't have an antiderivative. But I have had teachers say that we just don't know how to take the antiderivative of sinx/x. Someone else told me that you can find the antiderivative by using complex variables (but he might have just been high on crack).
Yes, it can be solved using complex variable calculus.

edit: I don't remember the specifics of it since it's been a few years since I took the class, but you had to do a path integral in the complex plane using Cauchy's theorem and subtract part of the path so that you're left with only the real portion
 

akubi

Diamond Member
Apr 19, 2005
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Originally posted by: Random Variable
Originally posted by: akubi
that's how it's done, SON.


ooooooooooooooh

Ok, but that just gives you a way to approximate the definite integral. It doesn't give you an antiderivative. And don't call me SON, son.

you editted your post from definite to indefinite after I replied
 
Aug 10, 2001
10,420
2
0
Originally posted by: akubi
Originally posted by: Random Variable
Originally posted by: akubi
that's how it's done, SON.


ooooooooooooooh

Ok, but that just gives you a way to approximate the definite integral. It doesn't give you an antiderivative. And don't call me SON, son.

you editted your post from definite to indefinite after I replied
An antiderivative is an indefinite integral not a definite integral. I made a mistake. :eek:
 
Aug 10, 2001
10,420
2
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Originally posted by: RaynorWolfcastle
Originally posted by: Random Variable
One of my old calculus textbooks says that you can prove that the sinx/x doesn't have an antiderivative. But I have had teachers say that we just don't know how to take the antiderivative of sinx/x. Someone else told me that you can find the antiderivative by using complex variables (but he might have just been high on crack).
Yes, it can be solved using complex variable calculus.

You get some function as your answer?
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
16
81
Originally posted by: Random Variable
Originally posted by: RaynorWolfcastle
Originally posted by: Random Variable
One of my old calculus textbooks says that you can prove that the sinx/x doesn't have an antiderivative. But I have had teachers say that we just don't know how to take the antiderivative of sinx/x. Someone else told me that you can find the antiderivative by using complex variables (but he might have just been high on crack).
Yes, it can be solved using complex variable calculus.

You get some function as your answer?
the integral from -infinity to infinity of sin(x)/x = pi. BTW, sin(x)/x is known as sinc(x) and is actually a very used function in electrical engineering because it is the Fourier transform of a square pulse

edit: I don't think this works for undefined integrals though and there were some formalisms about the way you went about it that I don't recall.
 

dainthomas

Lifer
Dec 7, 2004
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Originally posted by: Random Variable
One of my old calculus textbooks says that you can prove that the sinx/x doesn't have an antiderivative. But I have had teachers say that we just don't know how to take the antiderivative of sinx/x. Someone else told me that you can find the antiderivative by using complex variables (but he might have just been high on crack).


I do it all the time.