Originally posted by: minendo
Stop relying on the internet and a calculator you moron. The quadratic equation is easy enough for cigar smoking monkies to use.
Originally posted by: orakle22
[ -b +- sqrt(b^2 - 4ac) ] / 2a
or easier if you have a ti-83 or compatible calculator.. make a program and slap something like this in it:
Menu("Quad:","General",A,"Standard",B)
Lbl A
Prompt A,B,C
((4ac-B^2)/(4A))->K
((-B)/(2A))->H
Goto C
Lbl B
Prompt A,H,K
Goto C
Lbl C
Disp "X="
If ((-K/(A))<0
Then
Disp "NO SOL"
Else
Disp (H+root(-K/A)),(H-root(-K/A))
that should do it. .. just remember to use the actual right arrow (STO->) where i wrote ->
Originally posted by: Cha0s
ok, i have TI-83 Plus, where exactly do i start to write that program?
Originally posted by: Cha0s
ok, i have TI-83 Plus, where exactly do i start to write that program?
Originally posted by: KingNothing
x^2 + 5x - 4 = 0 factors into (x - 4) (x - 1) = 0, so x = 4 or 1
Originally posted by: KingNothing
x^2 + 5x - 4 = 0 factors into (x - 4) (x - 1) = 0, so x = 4 or 1
That doesn't matter. My retarded brother high on meth could still figure it out using the quadratic equation.Originally posted by: Cha0s
i need to use the calclulator, because the equations are complicated like 3434.34x^2 +53.33x-10^-5=0
Dude, No.Originally posted by: Cha0s
i need to use the calclulator, because the equations are complicated like 3434.34x^2 +53.33x-10^-5=0
Originally posted by: SaberDicer
Originally posted by: KingNothing
x^2 + 5x - 4 = 0 factors into (x - 4) (x - 1) = 0, so x = 4 or 1
Right idea but the factoring is off (if you foil -4 x -1 doesnt = -4)
I don't remeber how to factor it right this second though.
Originally posted by: Cha0s
i need to find x in x^2+5x-4=0 and other cubic/ quadratic equations. Is there a quick way to do it. (im a complete newb)
Originally posted by: amdfanboy
Originally posted by: Cha0s
i need to find x in x^2+5x-4=0 and other cubic/ quadratic equations. Is there a quick way to do it. (im a complete newb)
Enter equation into y=
2nd Calc, Find Zeros
Originally posted by: amdfanboy
Originally posted by: Cha0s
i need to find x in x^2+5x-4=0 and other cubic/ quadratic equations. Is there a quick way to do it. (im a complete newb)
Enter equation into y=
2nd Calc, Find Zeros
Originally posted by: Cha0s
Originally posted by: amdfanboy
Originally posted by: Cha0s
i need to find x in x^2+5x-4=0 and other cubic/ quadratic equations. Is there a quick way to do it. (im a complete newb)
Enter equation into y=
2nd Calc, Find Zeros
it gives me Left bound ? and i dont see the value