Fun maths problem...

Koing

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Object: To make 24 (putting 2 and 4 together is not the way!)

You have:

1, 3, 4 and 6

You can: *, /, +, -

You numbers 1, 3, 4 and 6 at ONLY ONCE.

You can also use the result in the next calculation. E.g. 4-1 = 3. Now you can use 3 (result from using 4 and 1) with the remaindnig numbers.

Harder then you think.

Koing

Sorry about that. None of you are correct. You can only use the numbers ONLY ONCE and the result of what you make once.
 

JustAnAverageGuy

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Aug 1, 2003
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(1+3) * 6 / 4 * 4

3 * 4 * (6 / 3) / 1

3 * 4 * (6 / 3) * 1

3 * 4 * 6 / 3 / 1

3 * 4 * 6 / 3 * 1

3 * 4 * (3 - 1) / 6 * 6

(6 - 1) * 4 + 3 + 1

(6 - 3) * 4 * (3 - 1)

(6 - 1) * (6 - 1) - (4 - 3)

4 * 6 / (3 / 3) / 1

(6^2 - 4^2) + 3 + 1

1, 3, 4, and 6
 

JustAnAverageGuy

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Originally posted by: eakers
they arent that smart, this is a repost.

I didn't see the repost, but this was an extremely easy problem. There are several solutions though.

Example


3 * 4 * (6 / 3) / 1
 

Koing

Elite Member <br> Super Moderator<br> Health and F
Oct 11, 2000
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Originally posted by: JustAnAverageGuy
Originally posted by: eakers
they arent that smart, this is a repost.

I didn't see the repost, but this was an extremely easy problem. There are several solutions though.

Example


3 * 4 * (6 / 3) / 1

That isn't right.

You used the 3 twice. You used it in the 3 * 4 to make 12. Then you used it again to do 6 / 3.

Here is a better example to highlight what you can do.

4-3 = 1
Now you can use the result 1 with remaining initial numbers (1, 6) that are left.

Koing

Ps didn't know it was a repost and I'm sure people would like a go at this.
 

Koing

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Oct 11, 2000
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Originally posted by: AsianriceX
1+3=4
4-4=0
0+4=4
4*6=24

right?

Nope.

You used the 4 twice here.

At that stage you only have 0 and 6 left. You used the 1, 3 and 4 up.

Koing
 

Koing

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Oct 11, 2000
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Originally posted by: JustAnAverageGuy
Originally posted by: Koing

When I made the answer, you say we had to use it atleast once. You didn't say we couldn't use it more :p

Yeah I know sorry I screwed it up originally :(

You can only use it ONLY ONCE now and whatever results you made.

Koing
 

Koing

Elite Member <br> Super Moderator<br> Health and F
Oct 11, 2000
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Originally posted by: JustAnAverageGuy
(6^2 - 4^2) + 3 + 1 ?

That is wrong.

You used 2 twice and you don't have 2 in the question but good try.

You only have

1, 3, 4 and 6.

Koing
 

BullsOnParade

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Apr 7, 2003
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LOL!!! Its Challenge 24 from Elementary School. I won for my school in 4th and 5th grade.
Hehe, let me see if i can find some of the 3 dot cards.
 

JustAnAverageGuy

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Originally posted by: Koing
Originally posted by: JustAnAverageGuy
(6^2 - 4^2) + 3 + 1 ?

That is wrong.

You used 2 twice and you don't have 2 in the question but good try.

You only have

1, 3, 4 and 6.

Koing

Would it help if I stated it as (6² - 4²) + 3 + 1 ?

Or did you mean that I used two of the numbers twice?
 

Yossarian

Lifer
Dec 26, 2000
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Originally posted by: JustAnAverageGuy
Originally posted by: Koing
Originally posted by: JustAnAverageGuy
(6^2 - 4^2) + 3 + 1 ?

That is wrong.

You used 2 twice and you don't have 2 in the question but good try.

You only have

1, 3, 4 and 6.

Koing

Would it help if I stated it as (6² - 4²) + 3 + 1 ?

Or did you mean that I used two of the numbers twice?

hello McFly, you can't use a 2, even as an exponent.
 

Hector13

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Apr 4, 2000
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6 * 4 = 24

or are you not explaining the part about having to use each number at least once?