- Feb 13, 2003
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So it's been about 20 years since I had stats class, but I was asked by someone if I could possibly help with figuring out the probability of a certain scenario.
There's 7 columns, and in each column you can have the number 0 - 7,550.
So for example, the numbers might be: 255 - 35 - 1- 0 - 0 - 0 -0
What I'm trying to do is figure out the probability of two lines having the same numbers.
So I think this would be P(total) = P(line1) * P(line2)
And P(line1) or P(line2) would be the probability of a unique line, say that example one above. Since each column can have number 0 - 7,550, and there's 7 columns that have numbers, I think it would be P(line) = 7551 ^ 7 = 1.39968817e27
So that's the probability of a single unique line. So for the probability of two lines having the same numbers, it would be: P(line1) * P(line2) = 1.39968817e27 * 1.39968817e27 = 1.04235006e39
Does that seem right? Don't have my old stats book to check if I'm modeling this right haha, and I dunno if I used the 'e' function right on the calculator.
There's 7 columns, and in each column you can have the number 0 - 7,550.
So for example, the numbers might be: 255 - 35 - 1- 0 - 0 - 0 -0
What I'm trying to do is figure out the probability of two lines having the same numbers.
So I think this would be P(total) = P(line1) * P(line2)
And P(line1) or P(line2) would be the probability of a unique line, say that example one above. Since each column can have number 0 - 7,550, and there's 7 columns that have numbers, I think it would be P(line) = 7551 ^ 7 = 1.39968817e27
So that's the probability of a single unique line. So for the probability of two lines having the same numbers, it would be: P(line1) * P(line2) = 1.39968817e27 * 1.39968817e27 = 1.04235006e39
Does that seem right? Don't have my old stats book to check if I'm modeling this right haha, and I dunno if I used the 'e' function right on the calculator.