Figuring out new complex number

Qacer

Platinum Member
Apr 5, 2001
2,721
1
91
Hey all,

I'm doing some impedance matching right now. I'm trying to tweak my Smith Chart readings so I get an exact impedance match. Here's what I'm trying to figure out. I have the following complex number: .04-j.42. Converted to admittance this would be: .224719 - j2.359.

I'm trying to find out what imaginary value I would get to get to an admittance with a real part of 1. In other words, I have .224719 - j2.359 and I want to end up at 1 - jX. How would I calculate the X? My brain is stuck figuring out how to figure out the imaginary part.

According to my Smith Chart estimates, that X is around -j4.95. I know my X should be around that value, but I want to find the exact number.

Can anyone help?

Thanks!
 

Qacer

Platinum Member
Apr 5, 2001
2,721
1
91
Doh! Thanks, f95toli! I feel so dumb by missing out that simple calculation.