Electricity question

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iwantanewcomputer

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Apr 4, 2004
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Originally posted by: JohnCU
Originally posted by: 91TTZ
Originally posted by: RaynorWolfcastle

As Heisenberg posted a while ago, the potential difference between two points is the integral of the E-field over a path between them. You can pick any path you want to integrate over because E-fields are conservative.

In this case, you can choose the wire, but since the E-field is essentially zero in the wire the integral will sum to zero and you will get 0V potential difference.
That's the long explanation, EM theory explanation.

As for needing to complete the circuit to measure something it's usually a case of practicality. That is, it's usually the easiest way although there may be solutions. You could, for example examine the orientation of polar molecules between the two points you're interested, but that's not really practical.

Just to give you an example where it's somewhat more practical: imagine an AC current flowing through a fixed, known resistance. Clearly there will be a time-varyin potential across the potential across the resistance. By Maxwell's equations (EM theory) we know that the AC current will give rise to a magnetic field. We could measure this magnetic field and use the known value of the resistance to calculate the time varying potential across it. In retrospect, that's not really all that practical, but the example stands.


edit: I apologize if this explanation flies over everyone's head, and confuses more than it helps; that's why I didn't post it in the first place.

While your response (and Heisenburg's) is correct, I think something needs to be said about tailoring the response to the level of the person who asked the question. A response could have been 100% correct but if it flew over the head of the person you were answering, it didn't help them out.

Thanks, but they don't have to dumb it down for me. I've had 2 physics courses and 4 calculus classes, I can follow. :)

this should be obvious after taking physics 2, but

electrons at the wall ground and the positive end of battery are at the same potential energy because there is nothing creating a potential diff. if you wonder why the wall ground doesn't act as a ground for the battery, it's cause the battey's voltage is between its terminals
 

JohnCU

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Originally posted by: cressida
The DC electric potential of a battery is created chemically within. Current is induced in a wire by electrons traveling from one side to the other. In the situation you described, there is no path for the electrons to travel from one terminal of the battery to the other, and therefore no Electric potential or "voltage" is present. This is called an open circuit.

AC is a little different in that the current is induced by the ever changing voltage of the supply. This allows current to flow through a circuit without the electrons ever returning to the source.

These all can be deduced from one of many textbooxs, online resources, high school physics teachers, and non-morons in general.

lol, wrong again. Never heard of open circuit voltage? It's call the Thevenin voltage.
 

TuxDave

Lifer
Oct 8, 2002
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Originally posted by: Heisenberg

It is a good analogy. I posted a similar explanation (minus analogy) near the beginning of the thread, but I guess nobody saw it.

Haha... sorry, but there was so many posts with so little information, I couldn't find it.
 

Heisenberg

Lifer
Dec 21, 2001
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Originally posted by: TuxDave
Originally posted by: Heisenberg

It is a good analogy. I posted a similar explanation (minus analogy) near the beginning of the thread, but I guess nobody saw it.

Haha... sorry, but there was so many posts with so little information, I couldn't find it.
No problem. :) Your analogy makes it much more understandable anyway.
 

Evadman

Administrator Emeritus<br>Elite Member
Feb 18, 2001
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My goodness. I haven't seen a thread with so many misconceptions in it for a while. Let's see what we can clear up.

#1. Residental AC
In a normal residental home, you have an available 240 volts, with 4 different leads. You have 2 hots, both with ~120v available. I say ~120v because in actuality, you can see anywhere from about 100 to 130 volts at any given moment on each lead. Now, the 2 hots are out of phase with each other by one wavelength. This means that 2 hots will give you ~240v (the wavelengths combine) or any single hot and the neutral will give you ~120v.

Now, the neutral is just that, neutral. IT IS NOT GROUND. Now, unless something is wrong witht he wiring in the home, there should be zero volts on this line. However, this line can be carying a good amount of amperage, but if the house was wired correctly, then the amperage on the line should be minimal (generaly less than 20 amps). If you look at your breaker pannel, you will notice 2 rows of breakers (in the vast majority of boxes) If you go down one side of the panel, the first breaker will be on one 120v line, the second will be on the other. (they are hooked to what are called Bus Bars)

Basicly, every other breaker is on the opposite line. This means that when the amperage is combined on the neutral, the amperage cancels out because theoreticly 1/2 of the amperage daw is exactly 180 degrees out of phase with the other half. This is why, generaly, neutral wires are 1/2 the gauge thickess (higher numericly) then the hots that supply them. (most residental is 2 4 gauge hots and an 8 gauge neutral return)

The ground line is just that, ground. There is either a 5' rod (or a few depending on soil conditions) hammered into the ground by your fuse panel, or a line from the ground bus bar to the water main (generally only if it is copper, but I have seen some on galvinized lines). If you have a line to the water main, then you should also have a jumper across the water meter, as the meter can stop the current flow under some conditions.

Now, a while ago, someone figured that having a voltage on the neutral was a bad thing (duh!) and the neutral bar is now required to be tied to the ground bar. This can be done a multitude of ways, but usually, there is an 8 gauge wire between the 2. Sometimes, in newer panels, and almost all J-Pannels, the neutral and ground bar are the same bar. What this does is cause a breaker trip if voltage is on the neutral bar. Theoreticly, any voltage on the neutral bar will pull an infinate amount of amps as there is no resistance, which will cause the offencing circit breaker to trop or the fuse to blow.

As a side effect to this, it is now required to ground the ductwork (hvac) in residental homes, as that was, in some instances, capable of having some voltage on it because of f'ed up wiring. Without the ground, there was no where for it to go. Well, not until you stepped onto the metal grate in the floor and got an owie. Ok, so that's residental wiring as applies to this discussion. Sorry it was so long.

#2. Automotive and dry cell batteries (DC)
First, AC works differently than DC. DC only goes in one direction, from positive to negitive right? Well, actually not. The electrons actually go from the negative side and fill in 'holes' in the positive side. In this instance, you need 2 things for current to flow. You need the electons, and you need the holes. Since you need both, only a hookup from the positive terminal of one battery, and the negitive terminal of the same battery will you get current flow. If you use one battery's positive and another batterys negitive, you will get exacly zero current flow. Now, as far as voltage is concerned, there is a 1.5v (or 12.6v for automotive) potential difference, but it can not be measured or used in any way. It is only there in a mathmaticl sense. Try it yourself on 2 different batteries. If you don't believe me, I have 2 fully charged automotive bats in my garage, I can take pics/

#3. Electrical meters
I am only going to go into volt meters for now so I can keep it simple. The way that most meters work is aparently misunderstood, even by some EE majors. Which really concerns me, and lays waste to my hope that the human race is getting smarter. Anyway...

Most volt meters do not mesure voltage. Let me repeat that, because it bares repeating. Volt meters do NOT measure voltage. In a perfect world, a voltmeter will have infinate resistance. However, I can not go to Radio Shack and order a resister with infinate ohms. Even special order! (what would the bands look like anyway? plaid?)

What is done is an extreamly high resistance resister is chosen (generally in the millions of ohms) and the AMPERAGE flowing though the COMPLETED circuit is how the voltage is computed. Because the meter actually measures AMPERAGE, the circut can not be energized, as the amperage flowing through the circuit can mess with the internal computations. That is why, on cheap meters, you get garbage when you measure voltage on a energized circuit.

As for the resister, (or resister block) the resister value is high for 2 reasons. The first is to limit the current in the circut as much as possible. More amperage means more heat, which means a larger and more expensive unit. The second is so that the meter can be as acutate as possible while still being made cheaply. Resisters generaly are within 5, 10 or 20% of their listed value. If you are measureing something with 1.5v and a resistance of a few million, being off by 5% on the few million side will result in a very small change in the reading.

A good analogy to the volt meter is a horsepower rating on engines. Engines to not make horsepower. engines make torque, or twisting force. Horsepower is just antoher way of measuring power output. Horsepower is computed by taking the torque, miltiplying it by the RPM the engine is at, and dividing by a contstant value, which is 5252. This means, given the same amount of torque, a higher reving engine will have more horsepower.

Back tot he volt meter. Since a connection between the positive side of a battery and the neutral or ground line on a home, or the negative of another battery for that mater, will not cause current to flow, then the volt meter can not read it, because as I said earlier, it measures AMPERAGE. Also, as I said, there is actually voltage potental there, it is just not measureable with a voltmeter.

#4. Conclusions
Everyone needs to shut the hell up and stop bashing other people and posters. In this entire thread, I see very few actual correct answers, only people trying to make their e-penis's bigger. If you are going to have a discusstion, great, have one. But don't start beinging insults into the mix, expecialy when you are insulting someone for being wrong, while you yourself is in the wrong. Now, this is not pointed at anyone in perticular, just OT in general. Ok, rant over. Enjoy the rest of the, hopefully civil, thread.

BTW Eli: I hope you enjoyed this really long post :p
 

cressida

Platinum Member
Sep 10, 2000
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Originally posted by: JohnCU
Originally posted by: cressida
The DC electric potential of a battery is created chemically within. Current is induced in a wire by electrons traveling from one side to the other. In the situation you described, there is no path for the electrons to travel from one terminal of the battery to the other, and therefore no Electric potential or "voltage" is present. This is called an open circuit.

AC is a little different in that the current is induced by the ever changing voltage of the supply. This allows current to flow through a circuit without the electrons ever returning to the source.

These all can be deduced from one of many textbooxs, online resources, high school physics teachers, and non-morons in general.

lol, wrong again. Never heard of open circuit voltage? It's call the Thevenin voltage.

You didn't read the first paragraph ? You are an annoying metrosexual. I bold it out for you.


 

blueshoe

Senior member
Mar 6, 2005
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I probably shouldn't even post because I'm only in my second year of high school physics, but here it goes..
I guess there's no voltage drop reading because there is no current going through the circuit, no amps no voltage drop reading? As for voltmeters having an infinitely high resistance-- you said there would be no current going through the wire anyway? But there would, because voltmeters must be connected in parallel anyway right?
Heh, I don't know too much about this stuff but that?s how I saw it...I'm gonna be going into EE too..


edit: spelling
 

JohnCU

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Originally posted by: cressida
Originally posted by: JohnCU
Originally posted by: cressida
The DC electric potential of a battery is created chemically within. Current is induced in a wire by electrons traveling from one side to the other. In the situation you described, there is no path for the electrons to travel from one terminal of the battery to the other, and therefore no Electric potential or "voltage" is present. This is called an open circuit.

AC is a little different in that the current is induced by the ever changing voltage of the supply. This allows current to flow through a circuit without the electrons ever returning to the source.

These all can be deduced from one of many textbooxs, online resources, high school physics teachers, and non-morons in general.

lol, wrong again. Never heard of open circuit voltage? It's call the Thevenin voltage.

You didn't read the first paragraph ? You are an annoying metrosexual. I bold it out for you.

Umm okay, ignoring the metro comment, which is a compliment thanks, I enjoy not looking like all the other geeks I go to class with... you just said there was no path and no voltage, there doesn't need to be a path for there to be voltage.
 

cressida

Platinum Member
Sep 10, 2000
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Originally posted by: JohnCU
Originally posted by: cressida
Originally posted by: JohnCU
Originally posted by: cressida
The DC electric potential of a battery is created chemically within. Current is induced in a wire by electrons traveling from one side to the other. In the situation you described, there is no path for the electrons to travel from one terminal of the battery to the other, and therefore no Electric potential or "voltage" is present. This is called an open circuit.

AC is a little different in that the current is induced by the ever changing voltage of the supply. This allows current to flow through a circuit without the electrons ever returning to the source.

These all can be deduced from one of many textbooxs, online resources, high school physics teachers, and non-morons in general.

lol, wrong again. Never heard of open circuit voltage? It's call the Thevenin voltage.

You didn't read the first paragraph ? You are an annoying metrosexual. I bold it out for you.

Umm okay, ignoring the metro comment, which is a compliment thanks, I enjoy not looking like all the other geeks I go to class with... you just said there was no path and no voltage, there doesn't need to be a path for there to be voltage.

*sigh* nevermind I forgot how EE likes to argue
 

JohnCU

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Originally posted by: cressida
*sigh* nevermind I forgot how EE likes to argue

Well, let's not argue, and try to tell me what you're saying. Look at your wall outlet, there is 120 V (rms) there, even though the two prongs aren't connected.
 

Omegachi

Diamond Member
Mar 27, 2001
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dude... haha this is funny... the positive going out of the battery needs negative going in... thats why circuits are called circuits...
 

Eli

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Oct 9, 1999
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Originally posted by: Evadman
BTW Eli: I hope you enjoyed this really long post :p
Yes, I did. ;)

Some of it was review. As i'm sure you remember, our houses wiring is a little wonky..

We get about 10VAC between anything metal plugged in and ground(the concrete floor).

20VAC on the dryer. Ouch. You learn quickly to never load wet clothes into the dryer barefoot.

:D
 

cressida

Platinum Member
Sep 10, 2000
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Originally posted by: JohnCU
Originally posted by: cressida
*sigh* nevermind I forgot how EE likes to argue

Well, let's not argue, and try to tell me what you're saying. Look at your wall outlet, there is 120 V (rms) there, even though the two prongs aren't connected.

Use this equation V = IR (gotta work tomorrow at 7am) let's start off easy with DC battery. The battery says 9volts, that 9 volts or "potential difference" is when there is a connection between the + and - for a chemical reaction to take place. Now the + / and - terminal has a lot of resistance so a connection is needed for the "potential difference" but then eventually over time there are leaks that's why battery has those expiration dates or "good till".

You said earlier the open voltage term ... well open circuit or whatever has no current flowing right? So let's go back to basics
V = IR no currnet V = 0 * R which is what?
 

QuitBanningMe

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Mar 2, 2005
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Originally posted by: Eli
Originally posted by: Evadman
BTW Eli: I hope you enjoyed this really long post :p
Yes, I did. ;)

Some of it was review. As i'm sure you remember, our houses wiring is a little wonky..

We get about 10VAC between anything metal plugged in and ground(the concrete floor).

20VAC on the dryer. Ouch. You learn quickly to never load wet clothes into the dryer barefoot.

:D
On the dryer. Hook your ground strap to the neutral post.

We have had this conversation before;)
 

JohnCU

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No, there is still 9 volts there. There is no current because R, for an open circuit, is infinity. And the limit as R -> inf. V/R = i = 0. There is no current, so there is no voltage drop in the circuit, so all the voltage remains over the battery.

Okay, look at it this way. 10v battery and a 1 ohm resistor in series. The current in the circuit is V/R = 10 amps. So, across the resistor, there is a 10 volt drop (IR = 10 V), just like Kirchoff said. You go up by 10 volts when you go over the battery, then down by 10. Just like going up and down stairs. Except, if you go up the stairs, and there is no way down, you're still at the top, at 10 V. :)
 

QuitBanningMe

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Originally posted by: cressida
Originally posted by: JohnCU
Originally posted by: cressida
*sigh* nevermind I forgot how EE likes to argue

Well, let's not argue, and try to tell me what you're saying. Look at your wall outlet, there is 120 V (rms) there, even though the two prongs aren't connected.

Use this equation V = IR (gotta work tomorrow at 7am) let's start off easy with DC battery. The battery says 9volts, that 9 volts or "potential difference" is when there is a connection between the + and - for a chemical reaction to take place. Now the + / and - terminal has a lot of resistance so a connection is needed for the "potential difference" but then eventually over time there are leaks that's why battery has those expiration dates or "good till".

You said earlier the open voltage term ... well open circuit or whatever has no current flowing right? So let's go back to basics
V = IR no currnet V = 0 * R which is what?

I just wanted to say that you are correct.
 

JohnCU

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Originally posted by: QuitBanningMe
Originally posted by: cressida
Originally posted by: JohnCU
Originally posted by: cressida
*sigh* nevermind I forgot how EE likes to argue

Well, let's not argue, and try to tell me what you're saying. Look at your wall outlet, there is 120 V (rms) there, even though the two prongs aren't connected.

Use this equation V = IR (gotta work tomorrow at 7am) let's start off easy with DC battery. The battery says 9volts, that 9 volts or "potential difference" is when there is a connection between the + and - for a chemical reaction to take place. Now the + / and - terminal has a lot of resistance so a connection is needed for the "potential difference" but then eventually over time there are leaks that's why battery has those expiration dates or "good till".

You said earlier the open voltage term ... well open circuit or whatever has no current flowing right? So let's go back to basics
V = IR no currnet V = 0 * R which is what?

I just wanted to say that you are correct.

Except that you're both wrong. :)

 

jagec

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Apr 30, 2004
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Originally posted by: Evadman
#1. Residental AC
In a normal residental home, you have an available 240 volts, with 4 different leads. You have 2 hots, both with ~120v available. I say ~120v because in actuality, you can see anywhere from about 100 to 130 volts at any given moment on each lead. Now, the 2 hots are out of phase with each other by one wavelength. This means that 2 hots will give you ~240v (the wavelengths combine) or any single hot and the neutral will give you ~120v.

By all means correct me if I'm wrong, but I was under the impression that your average 120V socket in a US home had 1 ground (basically copper pipe driven into the ground), 1 hot wire (where 120VAC is being supplied), and one cold wire (which is fundamentally exactly the same as the ground, and carries no voltage until you actually plug something in).

So if you connect a multimeter to the ground and the cold wire, you read 0 volts (nothing will flow). If you connect a multimeter to the ground and the hot wire, you will read 120V. And if you connect a multimeter to the hot and the cold wire, you will read 120V.

Finally, I was under the impression that if you really wanted to (and didn't mind breaking a LOT of building codes), you could run a single, hot wire into a house, and use that plus a copper spike driven into the ground, to wire your house. The cold wire is just there to provide a return path for the electricity when you plug stuff in.
 

Evadman

Administrator Emeritus<br>Elite Member
Feb 18, 2001
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Originally posted by: jagec
By all means correct me if I'm wrong, but I was under the impression that your average 120V socket in a US home had 1 ground (basically copper pipe driven into the ground), 1 hot wire (where 120VAC is being supplied), and one cold wire (which is fundamentally exactly the same as the ground, and carries no voltage until you actually plug something in).
You are correct when speaking on outlets. The vast majority of outlets in a home are 120v. there are generaly only 2 240v outlets in the home, one behind the stove and one by the dryer. These are 4 wire. 2 hots, a neutral (what you are calling the cold) and a ground. I was speaking of the entire electrical setup, not just a single 120v outlet.
Originally posted by: jagec
So if you connect a multimeter to the ground and the cold wire, you read 0 volts (nothing will flow). If you connect a multimeter to the ground and the hot wire, you will read 120V. And if you connect a multimeter to the hot and the cold wire, you will read 120V.
Correct.
Originally posted by: jagec
Finally, I was under the impression that if you really wanted to (and didn't mind breaking a LOT of building codes), you could run a single, hot wire into a house, and use that plus a copper spike driven into the ground, to wire your house. The cold wire is just there to provide a return path for the electricity when you plug stuff in.
No, not really. The last step of power transformation is done on one of the transformers that sit out on the power line poles. These convert the voltage in the lines to the 240 that goes into your house. Basicly, there are 3 taps on the the transformer, or Center Tap. one at each end, one in the middle. Each end gives you one phase of the 240v available. (180 degrees out of phase though, so the waves add to 240v). The neutral is the one in the middle.

This is important, and is why I expressly said the Neutral is not ground. Theoreticly, the neutral should have a zero volt potential between itself and ground. The neutral can vary in voltage from gound, but the 2 phases of hot are basicly marching in lockstep with the neutral, so they are always (hopefully) 120v higher than the neutral. For instance, the neutral could actually have a 10v difference between itself and ground. However, the 2 120v phases would now be at 130v relitive to ground, but still 120v relitive to neutral. Now, this should never happen, as the ground tie is there to hold the neutral at the same voltage potential as ground, or zero volts. If it wasn't tied to ground, you could get electrocuted when you touch, say, the TV and refrigerator at the same time. I don't know about you, but I like eating and watching TV at the same time.

Unless something goes wrong, through miswiring or a short, the ground wire should carry exacly zero amps. For lack of a better word, amperage should be coming 'in' on the 2 hot phases, and 'out' on the neutral phase back to the transformer. Now, in a 240v outlet, the 2 hots are where the current is flowing. Think of one hot being positive one hot being negitive. The voltage difference between the 2 is 240v. They switch positve and neg 120 times a second. There shouldn't be any current on the neutral line. the current goes from one side of the transformer, to the applaince, and back to the other side of the transformer, not to the neutral in the middle of the transformer. That is only used on 120v outlets/circuits. Now, quote a few 240v appliances have pieces that run at 120v. this is why there is a neutral available in the outlet, so there can be additional circuits in the appliance that are not 240v.

I have in and out in quotes because technicly, AC doesn't move all that far. Basicly, it ocilates or vibrates about 60 hertz.

 

QuitBanningMe

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I just wanted to say that you are correct.

Except that you're both wrong. :)

[/quote]

Ok. I'll remind the guys at work tommorow everything we learned about electricity is wrong.

Maybe I just read his post wrong. IDK.



Edit:NM I thought I quoted Evadman. Damn dragons
 

Eli

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Originally posted by: QuitBanningMe
Originally posted by: Eli
Originally posted by: Evadman
BTW Eli: I hope you enjoyed this really long post :p
Yes, I did. ;)

Some of it was review. As i'm sure you remember, our houses wiring is a little wonky..

We get about 10VAC between anything metal plugged in and ground(the concrete floor).

20VAC on the dryer. Ouch. You learn quickly to never load wet clothes into the dryer barefoot.

:D
On the dryer. Hook your ground strap to the neutral post.

We have had this conversation before;)
That would fix the problem with the dryer, I guess, but it happens with any appliance that is plugged in.

Fortunately a lot of the house is carpeted, so it doesen't seem to be that big of a deal I guess.

I can hold 1 lead of an LED in 1 hand, plant my feet against the concrete floor, and touch the other lead to my computer case and it will light.
 

Evadman

Administrator Emeritus<br>Elite Member
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Originally posted by: QuitBanningMe
Ok. I'll remind the guys at work tommorow everything we learned about electricity is wrong.

JohnCU is thinking voltage drop, and you are thinking voltage potential. They are 2 different things, but are both measured in volts. You two are violently agreeing. on 2 different topics.

Since both of you are more concerned about not looking foolish by giving incorrect information, you both are resorting to being whiney brats, without actually looking at what the other is actually saying. If either of you had actually read the other's posts, you would understand that. But you are both to busy insulting the other.

Originally posted by: Eli
I can hold 1 lead of an LED in 1 hand, plant my feet against the concrete floor, and touch the other lead to my computer case and it will light.
#1. Thats scary. Have you tried a ground strap between the neutral bar and the ground bar in your electricl panel? That should zero out the entire system. Or trip every breaker. one of the 2 :)

#2. Pics!
 

QuitBanningMe

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Originally posted by: Evadman
Originally posted by: QuitBanningMe
Ok. I'll remind the guys at work tommorow everything we learned about electricity is wrong.

JohnCU is thinking voltage drop, and you are thinking voltage potential. They are 2 different things, but are both measured in volts. You two are violently agreeing. on 2 different topics.

Since both of you are more concerned about not looking foolish by giving incorrect information, you both are resorting to being whiney brats, without actually looking at what the other is actually saying. If either of you had actually read the other's posts, you would understand that. But you are both to busy insulting the other.

Originally posted by: Eli
I can hold 1 lead of an LED in 1 hand, plant my feet against the concrete floor, and touch the other lead to my computer case and it will light.
#1. Thats scary. Have you tried a ground strap between the neutral bar and the ground bar in your electricl panel? That should zero out the entire system. Or trip every breaker. one of the 2 :)

#2. Pics!

Read the edit DICK.
 

Eli

Super Moderator | Elite Member
Oct 9, 1999
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Originally posted by: Evadman
Originally posted by: QuitBanningMe
Ok. I'll remind the guys at work tommorow everything we learned about electricity is wrong.

JohnCU is thinking voltage drop, and you are thinking voltage potential. They are 2 different things, but are both measured in volts. You two are violently agreeing. on 2 different topics.

Since both of you are more concerned about not looking foolish by giving incorrect information, you both are resorting to being whiney brats, without actually looking at what the other is actually saying. If either of you had actually read the other's posts, you would understand that. But you are both to busy insulting the other.

Originally posted by: Eli
I can hold 1 lead of an LED in 1 hand, plant my feet against the concrete floor, and touch the other lead to my computer case and it will light.
#1. Thats scary. Have you tried a ground strap between the neutral bar and the ground bar in your electricl panel? That should zero out the entire system. Or trip every breaker. one of the 2 :)

#2. Pics!
Someone say pics? :D

These are old. I should take some new, non-blurry ones. Would be able to see the LED and stuff better, too. This was back when I had an old Kodak 1mp cam, lol.

Dimly lit LED

Bad pic of voltmeter reading ~8VAC. It depends on how hard you press your feet against the concrete, how sweaty they are, etc. ;)