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Effin' integrals.

TridenT

TridenT

Lifer
They ain't so bad normally, but give me a problem like this:

"Use the properties of integrals to verify the inequality without evaluating the integrals."
rawrawrawrawawawawaaa.jpg


I'm not too aware of the properties of integrals when it relates to shit being under a squareroot that isn't able to be evaluated.
 
It's not like you have a life, you should have plenty of time to work on the question.

By the way, the answer is 3.

In all seriousness, don't let the square root thing fool you, the first thing your teacher should have taught you is that it's just an exponent of 1/2 so don't let it scare you.
 
lolz, this is fucking trivial. you are dumb aren't you.

if you post what progress you've made so far, maybe someone will take pity and post something useful.
 
RbSX said:
It's not like you have a life, you should have plenty of time to work on the question.

By the way, the answer is 3.

In all seriousness, don't let the square root thing fool you, the first thing your teacher should have taught you is that it's just an exponent of 1/2 so don't let it scare you.
Click to expand...

If I can't evaluate it though (i.e. integrate) then I don't see how I can show anything. It says just use properties of integrals. 😵 (Which I know, but don't see how those relate)
 
TridenT said:
If I can't evaluate it though (i.e. integrate) then I don't see how I can show anything. It says just use properties of integrals. 😵 (Which I know, but don't see how those relate)
Click to expand...

I'll admit that 'use the properties of integrals' is somewhat misleading. You have to start w/identifying properties (well, just one property) of the integrands.
 
busydude said:
Prove f(x)<=g(x) in that interval [0,1]....
Click to expand...

NOOOOOOOOoOOOoooooOO you gave it away

edit: though mad propz to anyone who can work out hte integral on the left by hand. I guessed (=bullshitted) the solution... it's really similar to integrating ln(x), something I assumed after integrating by parts. In this case, it helps to know that derivative of asinh(x) = 1/sqrt(1+x^2). It comes out to 1/2(x*sqrt(1+x^2) - asinh(x)). Not sure how that would've helped the OP even if he could derive it, lol.
 
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Good grief I don't miss that crap. Four quarters of engineering calculus, damn that was horrible. Of course now I have a job that requires all of a HS diploma, but I love it and I'm happy with it. I'll put that degree to use to get into grad school one day.
 
Definitely going to have to visit the tutoring center on Tuesday... this guy has assigned only 10 problems (one of which was something that I could do) but the rest are like "wtf..."

He is the worst math teacher I've ever had. He doesn't teach. He hasn't talked about any of this shit in class.
 
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