Originally posted by: SLCentral
Would I do:
(x^2+2xh+h^2)(x+h)
Originally posted by: schneiderguy
Originally posted by: SLCentral
Would I do:
(x^2+2xh+h^2)(x+h)
i think one of those +'s needs to turn into a minus sign.im just not sure which one
then again, i could and probably am completely wrong :Q
Originally posted by: her209
(x+h)(x+h)(x+h) = (x^2+2xh+h^2)(x+h)
Multiply each term using distributive law.Originally posted by: SLCentral
Originally posted by: her209
(x+h)(x+h)(x+h) = (x^2+2xh+h^2)(x+h)
Yeah, my big problem is that step right there. What should I do exactly after that?
Originally posted by: Stunt
(x+h)(x+h)(x+h) = (x^2+2xh+h^2)(x+h)
(x^2+2xh+h^2)(x+h) = x^3 + 3x^2h + 3xh^2 + h^3
Yeah you got it...![]()
Originally posted by: bctbct
damn that aint the basic algebra I remember, when did they add so many letters?![]()
Originally posted by: schneiderguy
Originally posted by: SLCentral
Would I do:
(x^2+2xh+h^2)(x+h)
i think one of those +'s needs to turn into a minus sign.im just not sure which one
then again, i could and probably am completely wrong :Q
Originally posted by: SLCentral
Originally posted by: Stunt
(x+h)(x+h)(x+h) = (x^2+2xh+h^2)(x+h)
(x^2+2xh+h^2)(x+h) = x^3 + 3x^2h + 3xh^2 + h^3
Yeah you got it...![]()
Sweet, that's what I'm getting. But now why am I not getting the right answer? I'm evaluating a difference quotiant, so throw that over h, and I should be getting 3x^2 +1.
Original problem: f(x) = x^3 + x
What I need to simplify:
(x+h)^3 + (x+h) -(x^3+x)
--------------------------------
h
So...
x^3 + 3x^2h + 3xh^2 + h^3 + x + h - x^3 -x
---------------------------------
h
Turns into...
3x^2h + 3xh^2 + h^3 + h
--------------------------------
h
Considering h=0, and is just used for simplifying, and the simplified answer SHOULD be 3x^2 + 1, what do I do next?
The only thing I see is to pull out the h:
h(3x^2 + 3xh + h^2 + 1)
But that leaves me with a unnecessary 3xh. What am I missing here?
Originally posted by: brikis98
Originally posted by: SLCentral
Originally posted by: Stunt
(x+h)(x+h)(x+h) = (x^2+2xh+h^2)(x+h)
(x^2+2xh+h^2)(x+h) = x^3 + 3x^2h + 3xh^2 + h^3
Yeah you got it...![]()
Sweet, that's what I'm getting. But now why am I not getting the right answer? I'm evaluating a difference quotiant, so throw that over h, and I should be getting 3x^2 +1.
Original problem: f(x) = x^3 + x
What I need to simplify:
(x+h)^3 + (x+h) -(x^3+x)
--------------------------------
h
So...
x^3 + 3x^2h + 3xh^2 + h^3 + x + h - x^3 -x
---------------------------------
h
Turns into...
3x^2h + 3xh^2 + h^3 + h
--------------------------------
h
Considering h=0, and is just used for simplifying, and the simplified answer SHOULD be 3x^2 + 1, what do I do next?
The only thing I see is to pull out the h:
h(3x^2 + 3xh + h^2 + 1)
But that leaves me with a unnecessary 3xh. What am I missing here?
a difference quotient is
lim h -> 0 [f(x+h) - f(x)] / h
so the numerator becomes
[(x+h)^3 + x + h] - x^3 - x
x^3 + 3hx^2 + 3xh^2 + h^3 + x + h - x^3 - x
3hx^2 + 3xh^2 + h^3 + h
h(3x^2 + 3xh + h^2 + 1)
dividing the numerator by the denominator cancels the h and we get:
lim h -> 0 3x^2 + 3xh + h^2 + 1 = 3x^2 + 1
which, as you'll learn, is precisely the derivative of f(x).
Originally posted by: probzy
I'm not good at math. Sorry.