What's so funny? It was a typo. I can't help it I type like sh!t and was tired. ground ground ground I usually read and edit for spelling and grammer , but as I said , I was tired.
What's so funny? It was a typo. I can't help it I type like sh!t and was tired. ground ground ground I usually read and edit for spelling and grammer , but as I said , I was tired.
The curvature is relavent because the path of the bullet is tangent to the curve of the earth. The further downrange it is, the further the earth is from the original path. In effect it has to fall further to hit the ground.
Satellites decay due to atmospheric drag. For low earth orbit satellites, such as skylab, the shuttle, ISS, etc. there is still enough atmosphere to slow it dow, and consequently lower the orbit. So occasionally they thrust the satellite to make it up. It's not to "defeat the pull of gravity".
You mean the gravitational pull of all celestial objects. You regularly take into account the effect of the sun & moon when calculating satellite orbits. As well as drag, as mentioned above, the shape of the earth, solar radiation pressure, etc.
In a physics textbook:
The point of this question is that you can separate horizontal and vertical velocities and accelerations and they are completely independant from each other.
Therefore with about four hundred thousand simplifying assumptions if the gun is perfectly horizontal the initial vertical velocity of the bullet when it leaves the tip of the rifle is 0. If you drop the other bullet at the precise instant the bullet leaves the tip of the rifle they both have an inital velocity of 0 and both come under the effect of the gravity (vertical acceleration) at the same instant so they will hit the ground at the same time (although obviously quite some horizontal distance apart).
< Edit > This is the Correct Answer (tm) if you are asked this question on a physics test/assignment. < /Edit >
In reality:
Who the hell knows. Even ignoring stuff like air resistance and terrain, the rifle probably isn't going to be perfectly level so it is going to have some initial vertical velocity (even if it's off by 1 degree). If it's angled up it will hit after the dropped bullet, and if angled down it will hit before. Throw in the other host of things simplified away by the physics textbook and the near impossibility of accurately measuring it and you end up at my initial four words: who the hell knows. Moreoever who the hell cares
The point of this question is that you can separate horizontal and vertical velocities and accelerations and they are completely independant from each other.
Therefore with about four hundred thousand simplifying assumptions if the gun is perfectly horizontal the initial vertical velocity of the bullet when it leaves the tip of the rifle is 0. If you drop the other bullet at the precise instant the bullet leaves the tip of the rifle they both have an inital velocity of 0 and both come under the effect of the gravity (vertical acceleration) at the same instant so they will hit the ground at the same time (although obviously quite some horizontal distance apart).
< Edit > This is the Correct Answer (tm) if you are asked this question on a physics test/assignment. < /Edit >
In reality:
Who the hell knows. Even ignoring stuff like air resistance and terrain, the rifle probably isn't going to be perfectly level so it is going to have some initial vertical velocity (even if it's off by 1 degree). If it's angled up it will hit after the dropped bullet, and if angled down it will hit before. Throw in the other host of things simplified away by the physics textbook and the near impossibility of accurately measuring it and you end up at my initial four words: who the hell knows. Moreoever who the hell cares
False. He was wrong, and now people are quoting him for truth. A few people, myself included, have explained it in detail.
Originally posted by: Noriaki
In a physics textbook:
The point of this question is that you can separate horizontal and vertical velocities and accelerations and they are completely independant from each other.
Therefore with about four hundred thousand simplifying assumptions if the gun is perfectly horizontal the initial vertical velocity of the bullet when it leaves the tip of the rifle is 0. If you drop the other bullet at the precise instant the bullet leaves the tip of the rifle they both have an inital velocity of 0 and both come under the effect of the gravity (vertical acceleration) at the same instant so they will hit the ground at the same time (although obviously quite some horizontal distance apart).
< Edit > This is the Correct Answer (tm) if you are asked this question on a physics test/assignment. < /Edit >
In reality:
Who the hell knows. Even ignoring stuff like air resistance and terrain, the rifle probably isn't going to be perfectly level so it is going to have some initial vertical velocity (even if it's off by 1 degree). If it's angled up it will hit after the dropped bullet, and if angled down it will hit before. Throw in the other host of things simplified away by the physics textbook and the near impossibility of accurately measuring it and you end up at my initial four words: who the hell knows. Moreoever who the hell cares
I like this answer the best.
Zenmervolt
Elite member
- Oct 22, 2000
- 24,514
- 44
- 91
Not only that, but unless the length of the gun's barrel is zero, then the fired bullet will hit infinitesimally later if you fire the gun at the same time as dropping the bullet. Now, if you drop the bullet at the same time as the fired bullet exits the barrel, they should hit at the same time assuming flat terrain (i.e. no curvature) and no atmosphere and constant gravity.
ZV
Physics World (i.e. infinatly flat plane, bullet 1 dropped exactly as bullet 2 leaves barrel, frictionless, etc.) = same time
Real World = who knows...depends what the terrain is like. Assuming flat/smooth terrain, the dropped bullet hits first.
/End of thread
****CONFIRMED****
Real World = who knows...depends what the terrain is like. Assuming flat/smooth terrain, the dropped bullet hits first.
/End of thread
****CONFIRMED****
Actually the dropped bullet would hit the ground first because everyone knows time slows down when bullets are shot. Ok, maybe not, but wouldnt it be cool if it did?
yukichigai
Diamond Member
- Apr 23, 2003
- 6,404
- 0
- 76
This is where the wrinkle is. Even neglecting air resistance, the distance the fired bullet travels will effectively increase the distance it has to fall, since the earth is not perfectly flat.
If you were somehow firing on a perfectly flat surface with uniform gravity along all areas of this flat surface (which is physically impossible) then the two would hit at the same time. Realistically the fired bullet would hit later, but the time difference would be so insignificant it wouldn't be noticable.
In the perfect world, they both hit at the same time.
However, the shot bullet must travel further (earth curves)
The shot bullet doesn't drop until it leaves the gun barrel meaning the dropped bullet has a higher vertical velocity before the shot bullet even begins to fall.
Assuming a perfect gun w\o recoil (i.e. barrel remains parallel after kickback, otherwise barrel would be aimed slightly up. )
Assuming the bullet neither gains or loses altitude due to the SHAPE of the bullet as it travels horizontally.
The dropped bullet will hit first, but the difference is so small that you could say it's the "same".
</didn't read the thread>
However, the shot bullet must travel further (earth curves)
The shot bullet doesn't drop until it leaves the gun barrel meaning the dropped bullet has a higher vertical velocity before the shot bullet even begins to fall.
Assuming a perfect gun w\o recoil (i.e. barrel remains parallel after kickback, otherwise barrel would be aimed slightly up. )
Assuming the bullet neither gains or loses altitude due to the SHAPE of the bullet as it travels horizontally.
The dropped bullet will hit first, but the difference is so small that you could say it's the "same".
</didn't read the thread>
Gunslinger08
Lifer
- Nov 18, 2001
- 13,234
- 2
- 81
Without reading 4 pages, I'm going to reply.
The shot bullet will hit first. Think about it: If they hit at the same time, it means they are travelling at the same speed. This would mean there was no difference between dropping a bullet onto your head from 4 feet and shooting you from 4 feet above. This would mean either a 4 foot drop would kill people, or no one could ever be shot from above.
The shot bullet will hit first. Think about it: If they hit at the same time, it means they are travelling at the same speed. This would mean there was no difference between dropping a bullet onto your head from 4 feet and shooting you from 4 feet above. This would mean either a 4 foot drop would kill people, or no one could ever be shot from above.
Gunslinger08
Lifer
- Nov 18, 2001
- 13,234
- 2
- 81
He said parallel to the dropped bullet. If he means firing it horizontally, he should say perpendicular to the dropped bullet. Assuming he means horizonally, and ignoring air resistance/bugs/curvature of the Earth/time for the firing pin to hit the bullet, they will hit the ground at the same time. In real life, the dropped bullet hits first.
No he didn't. Read it again.
"From 4' high you drop a bullet(without casing) and at the same moment you fire a gun exactly parallel to and 4' from the ground."
Parallel to the ground.
Gunslinger08
Lifer
- Nov 18, 2001
- 13,234
- 2
- 81
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