Definition help please

[ManyBeers]

....from a deck of 52 cards there are 311,875,200 possible?
.................................................and 2,598,960 possible?

Place the correct term after each statement:
Combinations
Permutations

 

[darkxshade]

# of Permutations > Combinations

 

[Mo0o]

Permutations are less I thought since order does matter. So AK is teh same as KA.

 

[Newbian]

If you are dealt 5 cards changes are you went over 21 and busted.

 

[darkxshade]

Originally posted by: Mo0o
Permutations are less I thought since order does matter. So AK is teh same as KA.

If the order does matter than AK & KA = 2 permutations
AK & KA is 1 combination(order doesnt' matter)

2 > 1

 

[ManyBeers]

Originally posted by: darkxshade

Originally posted by: Mo0o
Permutations are less I thought since order does matter. So AK is teh same as KA.

If the order does matter than AK & KA = 2 permutations
AK & KA is 1 combination(order doesnt' matter)

2 > 1

So there are 311,875,200 permutations. Is that right?
and 2,598,960 combinations. correct?

 

[darkxshade]

Originally posted by: ManyBeers

Originally posted by: darkxshade

Originally posted by: Mo0o
Permutations are less I thought since order does matter. So AK is teh same as KA.

If the order does matter than AK & KA = 2 permutations
AK & KA is 1 combination(order doesnt' matter)

2 > 1

So there are 311,875,200 permutations. Is that right?
and 2,598,960 combinations. correct?

Not going to do the math so all I can say is that # of combinations cannot be greater than permutations so if those numbers are accurate then yes.

 

[ElFenix]

it's actually a permutation lock.

 

[ManyBeers]

Originally posted by: darkxshade

Originally posted by: ManyBeers

Originally posted by: darkxshade

Originally posted by: Mo0o
Permutations are less I thought since order does matter. So AK is teh same as KA.

If the order does matter than AK & KA = 2 permutations
AK & KA is 1 combination(order doesnt' matter)

2 > 1

So there are 311,875,200 permutations. Is that right?
and 2,598,960 combinations. correct?

Not going to do the math so all I can say is that # of combinations cannot be greater than permutations so if those numbers are accurate then yes.

Thanks. I get the terms confused sometimes. The numbers are correct.