could use some calc/precalc help...

[zixxer]

okay with #2
given csc x = -3 and tan x > 0, find cos x

I used the identity csc x = 1/ sin x

ended up with sin x = 1/-3

then I'm stuck again.

 

[zixxer]

Originally posted by: DrPizza
Sorry if that sounds harsh, but it's the truth. If you're in pre-calculus, and have the textbook in front of you, yet can't figure out

given sin (pi/2-x)=2/7 find cos x

find all the solutions in the interval [0,2pie): csc x - 2 = 0

then you're in a world of trouble.

For the first problem, it's one of the identities. There's nothing to do. The answer is 2/7
sin(pi/2-x) EQUALS cos x

For the second problem, if you don't see that
cscx = 2
sin x = 1/2
(and what angles between 0 and 2pi have a sin value of 1/2? Hint: sin is positive in the 1st and 2nd quadrant. There are 2 answers.)

then you're in a world of trouble.

ok.. I use the unit circle and find the sin values that equal 1/2? that's 30deg and 150deg..... and I got a sin x = 1/-3... not 1/2...




it's too late to drop the class... or I would. 3 more weeks of hell

 

[toekramp]

Originally posted by: Nebor

Originally posted by: venk

Originally posted by: Nebor
The nerdy competitiveness of this board will save you money.

My Penis is bigger than your Penis.

I bet I can fit more of yours in my mouth than you can of mine in yours.

:disgust:

 

[maziwanka]

Originally posted by: Nebor
The nerdy competitiveness of this board will save you money.

 

[zixxer]

bump for edit

 

[dym]

attending your professor office hours would save you some $$$