iwantanewcomputer
Diamond Member
*******don't need to know this part to solve********
Just to explain, there is a .0047uf capacitor in series with a 47kohm resistor connected to ground. Vin is across both, Vout is across the resistor only. the transfer function, T(j w) = Vout/Vin [w=omega]
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given T(jw) = 1/(1+jwRC)
I need to derive |T(jw)| = 1/squareroot[1+(wRC)^2]
and the phase angle of T(jw) = - arctan(wRC)
Just to explain, there is a .0047uf capacitor in series with a 47kohm resistor connected to ground. Vin is across both, Vout is across the resistor only. the transfer function, T(j w) = Vout/Vin [w=omega]
**********************************
given T(jw) = 1/(1+jwRC)
I need to derive |T(jw)| = 1/squareroot[1+(wRC)^2]
and the phase angle of T(jw) = - arctan(wRC)