• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

chemistry question please help

Use the line equation.

0.145 mol x Vol per mole NA
------------------
1 mol

Edit: Eff it, you get the equation, even if the formatting gets messed up.
 
lol that is easy

1cubic cm = 1ml

just use the formulas they gave you/are in your book, lazy.

i think its .145 x that crazy number/1liter but im not sure, and i am most likely wrong, since i don't care enough to look it up since its not my homework.
 
1. Find the density of sodium metal in g/cm^3.
2. Find out how many grams .145 mole of sodium metal is by consulting a periodic table.
3. Multiply the number of grams of sodium metal by cm^3/g to get cm^3.
 
You'd need to know the atomic mass of sodium (look on periodic table) in order to answer that question. Use dimensional analysis to find out the mass of sodium you would need.

0.145mol Na ( 1g Na / ? mol Na) = g Na needed

Find ? by looking on the periodic table for sodium's atomic mass. This will give you the number of moles in 1g of Na.

After you find the mass of Na needed, cut a small piece of sodium and put it on a scale (be sure to put a watch glass on the scale and the sodium on the watch glass; rezero the scale after the mass of the watch glass alone has been found to get the mass of sodium only). If you need more, then cut more. If you need less, then remove some from your scale.

 
You must log in or register to reply here.

TRENDING THREADS

Back
Top