Can the average person bust through a door with those electromagnetic door locks?

[DrPizza]

I wonder if it's possible to use a 2nd electromagnet to weaken the field at the point where it holds the door? Alternately, could the discharge from a high capacity capacitor damage the coil somehow?

Or, perhaps an AC source with another coil outside the door to interfere with the DC current around the core on the electromagnet? I'm not going to think too deeply about this because, well, because Rubycon has already thought about this & has the answer. 😛

 

[lokiju]

I used to work for a security company that installed those as one of it's main bread and butters and those things will hold.

As others have said the door would break before the lock would give if it was installed right.

 

[Veramocor]

Just turn off the power...lock disabled. 😛

You asked for a miracles. I give you the F B I.

 

[Jzero]

most secured govt rooms have the mag lock (24v) on an battery UPS circuit, usually rated for 2hrs. but within 5min, the backup diesal generators should kick in

a better way is just trip the fire alarm. 😱

If the lock has a battery backup to survive a power failure, chances are it is also configured not to drop when the fire alarm goes off.

 

[Rubycon]

If the lock has a battery backup to survive a power failure, chances are it is also configured not to drop when the fire alarm goes off.

That would depend on where the door leads.
If the door leads to a secured area there is usually a pushbutton to release it INSIDE the secured area so someone INSIDE the secured area can get out any time.

From OUTSIDE the secured area people without a pass or holding a pass with insufficient privs are not going to open it. Usually planned escape routes don't go through secured areas. In this case fire alarm signaling will NOT disengage electromagnet power.