Can someone show me how to do this math problem?

alexjohnson16

Platinum Member
Dec 27, 2002
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How many three - letter and three - digit license plates can be made if no digits can be repeated?

I have no clue how to do this. I know it involves factorials, but I just don't know how to get this done.
 

b0mbrman

Lifer
Jun 1, 2001
29,470
1
81
Originally posted by: alexjohnson16
How many three - letter and three - digit license plates can be made if no digits can be repeated?

I have no clue how to do this. I know it involves factorials, but I just don't know how to get this done.

26 x 25 x 24 x 10 x 9 x 8 x 1 x 2 x 3 x 4 x 5 x 6

booya!

[Edit] Guess I didn't do much showing :confused:
 

MartyMcFly3

Lifer
Jan 18, 2003
11,436
29
91
www.youtube.com
26 letters in the alphabet.
10 numbers (0-9).

No repeats.

So you have 26 options for letter A. 25 options for letter B. 24 options for letter C.
And you also have 10 options for number A. 9 options for number B. 8 options for number C.

26*25*24*10*9*8 = 11,232,000 possible combinations.
 
Apr 17, 2005
13,465
3
81
Originally posted by: b0mbrman
Originally posted by: alexjohnson16
How many three - letter and three - digit license plates can be made if no digits can be repeated?

I have no clue how to do this. I know it involves factorials, but I just don't know how to get this done.

26 x 25 x 24 x 10 x 9 x 8 x 1 x 2 x 3 x 4 x 5 x 6

booya!

ka sha
 

Brackis

Banned
Nov 14, 2004
2,863
0
0
Out of curiosity for a cobwebbed mind...does this come out to be a simple combination/permutation?
 

b0mbrman

Lifer
Jun 1, 2001
29,470
1
81
Originally posted by: MartyMcFly3
26 letters in the alphabet.
10 numbers (0-9).

No repeats.

So you have 26 options for letter A. 25 options for letter B. 24 options for letter C.
And you also have 10 options for number A. 9 options for number B. 8 options for number C.

26*25*24*10*9*8 = 11,232,000 possible combinations.

Don't forget to shuffle up the numbers and letters once you have them selected ;)
 

So

Lifer
Jul 2, 2001
25,923
17
81
if letters and numbers CAN be repeated:
26^3*10^3
if letters CANNOT be repeated and numbers CAN be repeated:
26*25*24*10^3
if letters CAN be repeated and numbers CANNOT be repeated:
26^3*10*9*8
if neither letters nor numbers can be repeated:
26*25*24*10*9*8
 

MartyMcFly3

Lifer
Jan 18, 2003
11,436
29
91
www.youtube.com
Originally posted by: b0mbrman
Originally posted by: MartyMcFly3
26 letters in the alphabet.
10 numbers (0-9).

No repeats.

So you have 26 options for letter A. 25 options for letter B. 24 options for letter C.
And you also have 10 options for number A. 9 options for number B. 8 options for number C.

26*25*24*10*9*8 = 11,232,000 possible combinations.

Don't forget to shuffle up the numbers and letters once you have them selected ;)

Good point. If its just 3 letters then 3 numbers then it's good though. :p OP left out some details.
 

bleeb

Lifer
Feb 3, 2000
10,868
0
0
Originally posted by: So
if letters and numbers CAN be repeated:
26^3*10^3
if letters CANNOT be repeated and numbers CAN be repeated:
26*25*24*10^3
if letters CAN be repeated and numbers CANNOT be repeated:
26^3*10*9*8
if neither letters nor numbers can be repeated:
26*25*24*10*9*8

you OWN this problem. good job!
 

hypn0tik

Diamond Member
Jul 5, 2005
5,866
2
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26*25*24*10*9*8 (Edit: Assuming of course, neither letters nor numbers can be repeated).

That's ONLY to pick all the letters and number. Now, within the 6 you pick, they can be arranged in 6! ways to give you unique license plates. Hence, you have:

26*25*24*10*9*8*6!
 

her209

No Lifer
Oct 11, 2000
56,336
11
0
Wouldn't some permutation of letters be counted multiple times, e.g. AAA123?
 

shira

Diamond Member
Jan 12, 2005
9,500
6
81
Just realized. This has to be broken into three cases:

Three different letters: 26*25*24*10*9*8*6!

Two different letters: 26*1*25*10*9*8*6!/2!

All letters the same: 26*1*1*10*9*8*6!/3!


Total license plates is the sum of those three values.
 

alexjohnson16

Platinum Member
Dec 27, 2002
2,074
0
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Argh, everyone's answer is different.

I wish I had this actual class instead of online, its more difficult to learn on the internet.
 

eelw

Lifer
Dec 4, 1999
10,349
5,497
136
Originally posted by: Vegitto
A123AA?

Is that even a valid plate? And there would be even more combinations here in Ontario since we have 4 letter and 3 number plates.