Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
waggy
No Lifer
- Dec 14, 2000
- 68,143
- 10
- 81
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: So
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
I would like someone to explain what impulse is occuring that stops the acceleration. If you are accelerating and let off the gas, you still have the force of the acceleration behind you, you cant be accelerating at 10 m/s^2, let off the gas and all the sudden be at 0 m/s^2... there is a time during which you are still accelerating albeit in a continuously declining amount until the time at which you reach 0 (and begin to decelerate).</end quote></div>
Wow.
Just...
...wow.</end quote></div>
Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
</end quote></div>
err. yeah the force does go to ZERO.
so when FORCE=zero ACCELERATION=zero.
<div class="FTQUOTE"><begin quote>Originally posted by: So
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
I would like someone to explain what impulse is occuring that stops the acceleration. If you are accelerating and let off the gas, you still have the force of the acceleration behind you, you cant be accelerating at 10 m/s^2, let off the gas and all the sudden be at 0 m/s^2... there is a time during which you are still accelerating albeit in a continuously declining amount until the time at which you reach 0 (and begin to decelerate).</end quote></div>
Wow.
Just...
...wow.</end quote></div>
Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
</end quote></div>
err. yeah the force does go to ZERO.
so when FORCE=zero ACCELERATION=zero.
Yes it is acceleration, and the force is a result of the ACCELERATION and MASS... it causes the force that allows the car to continue to accelerate.
The force does not go down to zero, thats stupid, if it went to 0 does that mean if I run into something at 100 miles an hour as long as I let off the gas it will be a light impact and no damage will be sustained?
You are obviously having trouble understanding.... If you are accelerating, there is a force present, if you remove the force, you dont instantly stop accelerating, the force of drag takes over and begins to decrease your rate of acceleration until the time at which the forces become balanced!
I suspect you havent taken physics, Im a B. Eng with a specialization in solid mechanics.... This is my area of knowledge
waggy
No Lifer
- Dec 14, 2000
- 68,143
- 10
- 81
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: waggy
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: waggy
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: So
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
I would like someone to explain what impulse is occuring that stops the acceleration. If you are accelerating and let off the gas, you still have the force of the acceleration behind you, you cant be accelerating at 10 m/s^2, let off the gas and all the sudden be at 0 m/s^2... there is a time during which you are still accelerating albeit in a continuously declining amount until the time at which you reach 0 (and begin to decelerate).</end quote></div>
Wow.
Just...
...wow.</end quote></div>
Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
</end quote></div>
err. yeah the force does go to ZERO.
so when FORCE=zero ACCELERATION=zero.
</end quote></div>
The force does not go down to zero, thats stupid, if it went to 0 does that mean if I run into something at 100 miles an hour as long as I let off the gas it will be a light impact and no damage will be sustained?
</end quote></div>
have you taken physics? do understand what force is?</end quote></div>
I suspect you havent taken physics, Im a B. Eng with a specialization in solid mechanics.... This is my area of knowledge
</end quote></div>
damn. i would ask for a refund.
edit: yes i have taken phsyics.
i soppose they came up with something ot change the fact that F=MA i mean i could be wrong. it has been 7 years or so since i have taken physics.
<div class="FTQUOTE"><begin quote>Originally posted by: waggy
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: waggy
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
<div class="FTQUOTE"><begin quote>Originally posted by: So
<div class="FTQUOTE"><begin quote>Originally posted by: RGUN
I would like someone to explain what impulse is occuring that stops the acceleration. If you are accelerating and let off the gas, you still have the force of the acceleration behind you, you cant be accelerating at 10 m/s^2, let off the gas and all the sudden be at 0 m/s^2... there is a time during which you are still accelerating albeit in a continuously declining amount until the time at which you reach 0 (and begin to decelerate).</end quote></div>
Wow.
Just...
...wow.</end quote></div>
Please, go ahead and explain to me what instant massive force takes acceleration from 10m/s^2 to 0 in an instant.
</end quote></div>
err. yeah the force does go to ZERO.
so when FORCE=zero ACCELERATION=zero.
</end quote></div>
The force does not go down to zero, thats stupid, if it went to 0 does that mean if I run into something at 100 miles an hour as long as I let off the gas it will be a light impact and no damage will be sustained?
</end quote></div>
have you taken physics? do understand what force is?</end quote></div>
I suspect you havent taken physics, Im a B. Eng with a specialization in solid mechanics.... This is my area of knowledge
</end quote></div>
damn. i would ask for a refund.
edit: yes i have taken phsyics.
i soppose they came up with something ot change the fact that F=MA i mean i could be wrong. it has been 7 years or so since i have taken physics.
So
Lifer
- Jul 2, 2001
- 25,923
- 17
- 81
Low Post Count Member? Check.
Suspiciously heated argument? Check.
No understanding of topic at hand? Check.
Strange abbreviation of claimed credentials? Check.
Lets see what my magic 8-ball says.
"Magic 8-ball, is this man a B.S. M.E.?"
<shakes ball>
"Signs point to no."
GasX
Lifer
- Feb 8, 2001
- 29,033
- 6
- 81
F=MA
you get that right?
F in this case is equal to F1 - F2 - F3
F1 is equal to the force generated by the engine as transmitted through the clutch to the wheels
F2 is equal to the road/tire friction
F3 = wind resistance
All three forces are constantly variable
F1 is directly proportional to the throttle setting obviously
F1 is also reduced by clutch slippage
F1 is intantaneously ZERO as soon as the clutch disengages
If the gas is let off or the clutch partially depressed, F1 will drop. If it drops below F2 + F3, the vehicle slows down. As soon as the throttle is let go or the clutch disengages, F1 is instantaneously ZERO. The net result is F immediately goes to a NEGATIVE value and deceleration commences.
When I think of a rocket ship in space accelerating at a certain rate and then instantaneously cuts its thrust off I don't see it magically continuing to accelerate for a brief period to an even greater speed. Less so likely in a non-vacuum, frictional environment.
nakedfrog
No Lifer
- Apr 3, 2001
- 62,742
- 18,922
- 136
Let me see if I have the same understanding of the word "acceleration" as you do.
As I understand it, acceleration is the act of going faster.
Thus, by my understanding, once you put the transmission in neutral, you cease gaining speed, and thus, are not going faster than you were before you put the transmission in neutral.
No, I haven't taken physics, this is just a layman's view of the situation.
Im sorry to disappoint but I indeed am a Mechanical Engineer.
I dont know how else to explain this to you.... Just, look at all the forces in the system, without an impulse you CANNOT just go from accelerating to not, you have to have a linear (or parabolic) transition. There are no impulses!! The removal of the engines force will mean that it is no longer able to sustain its acceleration oppoising drag and the acceleration will begin to decline until it is zero.
Aikouka
Lifer
- Nov 27, 2001
- 30,383
- 912
- 126
Acceleration does not exist in any state without a force to cause it. This also includes the "opposite" deceleration. The idea of "acceleration" is like the wiktionary definition of "(transitive) To cause to move faster; to quicken the motion of; to add to the speed of." Unless the bike is on a decline when the clutch is engaged, there will be 0 forces acting on the bike to provide any momentum and in fact, the forces will provide deceleration.
Although... technically, acceleration does include deceleration. So until the guy stops, he is still accelerating, but in a negative (i.e. decelerating) manner.
EDIT: So in other words, as humans think it... he is not accelerating. As a physicist would explain it, he is but in a negative (i.e. deceleration) manner.
GasX
Lifer
- Feb 8, 2001
- 29,033
- 6
- 81
A further point of clarification:
If you let off the gas, there is a small lag and force will still be present momentarily.
However, I will re-emphasize that as soon as the clutch is disengaged, acceleration is impossible except that due to gravity. If I rode off a cliff and let off the sag and clutch, I am fairly sure there would be a brief moment of acceleration followed by a traumatic decceleration...
If you let off the gas, there is a small lag and force will still be present momentarily.
However, I will re-emphasize that as soon as the clutch is disengaged, acceleration is impossible except that due to gravity. If I rode off a cliff and let off the sag and clutch, I am fairly sure there would be a brief moment of acceleration followed by a traumatic decceleration...
NO THE PLANE DOES NOT TAKE OFF UNLESS HE LETS OFF THE CLUTCH AT .9999999999999999999999999999 SECONDS AND HAS BULK BEEF IN THE SIZE OF AN ALTENATOR THAT A MOUSE JUST POPPED OUT OF WITH A 5G BAG OF COOL YOUR CPU WITH SOLUTION!!!!!!!!
For me thinking about it this way clears up the argument: acceleration is the second derivative of position, velocity is the first derivative of position, therefore acceleration is the first derivative of velocity....i.e. the rate of change of velocity [(m/s)/s]. When the clutch is engaged, and assuming (rightly) there are forces attempting to slow the bike down (i.e. friction in wheels and air resistance, etc.), the velocity continues to go up for a time, but the rate of change of velocity (i.e. acceleration) goes down, and therefore the bike is decelerating.
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