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Can anyone help me figure out this Calculus problem involving work/force?

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Lol, on the fifth attempt, 21506388 works. I am very happy, only lost .5 out of 1 mark on that question, so maybe lost .005% overall, Is there anyway you can show me how you got 21506388? My friend have the same question except radius is 24ft and height is 29feet
 
dam that really sucks, i should have known better i

i used the same integral i had before 0-20 of (11y/10)^2 (dy) (62.4) (19+y)


it was that supid underground tank, you were right, you have to account for teh fact that it is underground.

like for example if it were above ground then the distance would be (19-y) but since its below ground the difference between the each disk would be (y - (-19) or y+19
 
to make it up ill try to do your friends problem.

should be integral of 0-20, (pi)(24y/29)^2(62.4)(19+y) dy

edit for some corections
 
I'm not getting the same result with the integral you posted.

"0-20 of (11y/10)^2 (dy) (62.4) (19+y)"

is that integral of {(11y/10)^2 * 62.4 * (10+y)} evaluated from 0 - 20? cause that integral i am getting 6845696 using my calculator
 


<< Hmm, but I used (39-y), so that does not explain it for me.
I need to figure out my mistake. >>



ya that was your mistake you shouldnt have used 39-y, if you use 19+y then you will probblay get the right answer.

you have to add 19+y because image an x,y coordinate plane with the line y=0 being ground level, since the tank is at -19, to find a distance, you would add 19 to whatever y value you would have
 


<< I'm not getting the same result with the integral you posted.

"0-20 of (11y/10)^2 (dy) (62.4) (19+y)" >>



you forgot PI
 
Hmm, I see what you mean.
But that way, you count y from 0 on...
but when y = 0 in your scenario, the radius r=22 feet, but your result would give r=0 feet

I am confused, but glad that you got the right answer!

Congrats Alee!!!!
 


<< Hmm, I see what you mean.
But that way, you count y from 0 on...
but when y = 0 in your scenario, the radius r=22 feet, but your result would give r=0 feet

 >>



yes i am counintg y as 0 on...

thats true when y = 0 the radius will be 0 becasue remember its a cone (and 0 height (very very bottom tip of a cone (bascially a point) will result with a radius of 0
 
But in your reference frame, the tip is x=20 ft.
It doesn't matter, your solution is the correct one.

Good night!

EDIT: HAH! I got it. We pump the water into the base, and have to push against the hydrostatic force. It makes much more sense that way. Oh, I am such an idiot.
 
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