calling the calculus 3 gods

[Oscar1613]

you missed a negative in fx but, yeah it doesnt work....

 

[MichaelD]

Oh...I get it:

Lagrange

It's about prostitution!!!! LIke in the ZZ Top song of the same name

Rumor spreadin' round
In that Texas town
About that shack
Outside Lagrange
They gotta lotta nice girls there!

So, Calculus is about sex, right?

 

[Oscar1613]

guess i should start distributing:
D=2e^(-x^2 - y^2)*(1-5x^2-2y^2+4x^4+8x^2 y^2)*2e^(-x^2 - y^2)*(2-x^2-10y^2+2x^2 y^2+4y^4) - [4ye^(-x^2 - y^2)*(2x^4+8x^2 y^2+8x^2 y-5x^2-2y^2-10]^2
:disgust::|:Q:frown:

 

[Ionizer86]

So, Calculus is about sex, right?

Lol, if it was that simple Actually, we do stuff like find minimums on functions and slopes of equations at points, and we find volumes of random geometric shapes. Fun huh?

 

[dighn]

try converting to polar

f = e^(-x^2 - y^2)*(x^2 + 2y^2)

f = e^(-r^2)*r^2(1 + sin^2o)

df/do = 2sinocoso * (e^(-r^2)*r^2)
df/do = sin2o * (e^(-r^2)*r^2) = 0
right side is never 0 (the r stuff)

sin2o is 0, o must be 0, or pi/2 for a circle (interval of o is 0 - 2pi)

df/dr = e^(-r^2)*-2r*r^2(1+sin^2o) + e^(-r^2)*2r(1+sin^2o)
df/dr = e^(-r^2)*2r*(1+sin^2o)(-r^2 + 1)

= zero when r = 0, -1, 1

so r = 0, -1, 1, o = 0, pi/2

f = e^(-r^2)*r^2(1 + sin^2o)

for r = 0, f = 0

for r = -1,1, f = e^-1(1+sin^2o)
---for o = 0, f = e^-1
---for o = pi/2 f = 2e^-1
then you test the boundary disk, r = 2
f = 4e^-4(1+sin^2o) where o = 0 to 2pi, obviously maximum is when o
is pi/2 or 3pi/2 and f is 8e^-4. min is well bigger than zero


min is 0, max is either 2e^-1 or 8e^-4 which is 2^3*e^-4, 2^e-1 is bigger or max

did this fast so if it's wrong... dont blame me

 

[MichaelD]

Originally posted by: Oscar1613
guess i should start distributing:
D=2e^(-x^2 - y^2)*(1-5x^2-2y^2+4x^4+8x^2 y^2)*2e^(-x^2 - y^2)*(2-x^2-10y^2+2x^2 y^2+4y^4) - [4ye^(-x^2 - y^2)*(2x^4+8x^2 y^2+8x^2 y-5x^2-2y^2-10]^2
:disgust::|:Q:frown:

You eternally suck Lucifer's Schlong forever, simply for posting such an inhumanly unsolveable equation. God himself would smack you. Two times.

 

[RaynorWolfcastle]

Originally posted by: MichaelD

Originally posted by: Oscar1613
guess i should start distributing:
D=2e^(-x^2 - y^2)*(1-5x^2-2y^2+4x^4+8x^2 y^2)*2e^(-x^2 - y^2)*(2-x^2-10y^2+2x^2 y^2+4y^4) - [4ye^(-x^2 - y^2)*(2x^4+8x^2 y^2+8x^2 y-5x^2-2y^2-10]^2
:disgust::|:Q:frown:

You eternally suck Lucifer's Schlong forever, simply for posting such an inhumanly unsolveable equation. God himself would smack you. Two times.

Michael, you're not an engineering major are you? In engineering, we have a word for problems like this, we call them "trivial"

 

[MichaelD]

Originally posted by: RaynorWolfcastle

Originally posted by: MichaelD

Originally posted by: Oscar1613
guess i should start distributing:
D=2e^(-x^2 - y^2)*(1-5x^2-2y^2+4x^4+8x^2 y^2)*2e^(-x^2 - y^2)*(2-x^2-10y^2+2x^2 y^2+4y^4) - [4ye^(-x^2 - y^2)*(2x^4+8x^2 y^2+8x^2 y-5x^2-2y^2-10]^2
:disgust::|:Q:frown:

You eternally suck Lucifer's Schlong forever, simply for posting such an inhumanly unsolveable equation. God himself would smack you. Two times.

Michael, you're not an engineering major are you? In engineering, we have a word for problems like this, we call them "trivial"

No. I'm not that bright. But at least I admit it. My strong suite is the spoken word/grammar/composition/comprehension, etc...all that literary crap. I'm a dumbass when it comes to math. All that right brain/left brain bxllshit.

 

[silverpig]

Go to polar. Your x^2 + 2y^2 = r^2 + 2r^2 cos^2(theta)

Do your Fr and F(theta), D thing, to check for max/min inside the disk. You then have to check the boundaries, so sub in r = 2 (x^2 + y^2 = 2^2) and check for which values of theta you have a max and min.

 

[Oscar1613]

Originally posted by: MichaelD

Originally posted by: Oscar1613
guess i should start distributing:
D=2e^(-x^2 - y^2)*(1-5x^2-2y^2+4x^4+8x^2 y^2)*2e^(-x^2 - y^2)*(2-x^2-10y^2+2x^2 y^2+4y^4) - [4ye^(-x^2 - y^2)*(2x^4+8x^2 y^2+8x^2 y-5x^2-2y^2-10]^2
:disgust::|:Q:frown:

You eternally suck Lucifer's Schlong forever, simply for posting such an inhumanly unsolveable equation. God himself would smack you. Two times.

help! i'm being oppressed!

Originally posted by: dighn
try converting to polar

f = e^(-x^2 - y^2)*(x^2 + 2y^2)

f = e^(-r^2)*r^2(1 + sin^2o)

df/do = 2sinocoso * (e^(-r^2)*r^2)
df/do = sin2o * (e^(-r^2)*r^2) = 0
right side is never 0 (the r stuff)

sin2o is 0, o must be 0, or pi/2 for a circle (interval of o is 0 - 2pi)

df/dr = e^(-r^2)*-2r*r^2(1+sin^2o) + e^(-r^2)*2r(1+sin^2o)
df/dr = e^(-r^2)*2r*(1+sin^2o)(-r^2 + 1)

= zero when r = 0, -1, 1

so r = 0, -1, 1, o = 0, pi/2

f = e^(-r^2)*r^2(1 + sin^2o)

for r = 0, f = 0

for r = -1,1, f = e^-1(1+sin^2o)
---for o = 0, f = e^-1
---for o = pi/2 f = 2e^-1
then you test the boundary disk, r = 2
f = 4e^-4(1+sin^2o) where o = 0 to 2pi, obviously maximum is when o
is pi/2 or 3pi/2 and f is 8e^-4. min is well bigger than zero


min is 0, max is either 2e^-1 or 8e^-4 which is 2^3*e^-4, 2^e-1 is bigger or max

did this fast so if it's wrong... dont blame me

OMG! thanks a bunch... i got alot of that, but stupid me thought i wrote sin 2o, not sin^2 o... that makes it alot easier

 

[MichaelD]

Sin is sin , dammit. The bible says so. None of this "Sin2" bullsh1t.

 

[beer]

Originally posted by: MichaelD
Speaking strictly as someone who is Mathematically Challenged; what the fvck is the point to an equation like this?

Can you build a bridge with it? Can you cure cancer? Can you find out EXACTLY how many apples Suzy has in her cart, being that Matthew's train left NYC four hours ago, traveling at an average rate of 34.13 KM/s?

I mean, really! That's just a SICKASS equation!

A lot of times, Calculus looks complicated but when you simplify everything, it works out nicely. Sometimes there are problems in calculus that are deceptively hard (some integrations) that look easy, and some really rediculous-looking ones that simplify quite nicely

 

[MichaelD]

Originally posted by: Elemental007

Originally posted by: MichaelD
Speaking strictly as someone who is Mathematically Challenged; what the fvck is the point to an equation like this?

Can you build a bridge with it? Can you cure cancer? Can you find out EXACTLY how many apples Suzy has in her cart, being that Matthew's train left NYC four hours ago, traveling at an average rate of 34.13 KM/s?

I mean, really! That's just a SICKASS equation!

A lot of times, Calculus looks complicated but when you simplify everything, it works out nicely. Sometimes there are problems in calculus that are deceptively hard (some integrations) that look easy, and some really rediculous-looking ones that simplify quite nicely

When the second coming of Christ happens; if he's sick that day, you can fill in for him...I'd believe you.

All this stuff is so far above my head...X+3+5. <--I can solve that one b/c it's logical...it has a beginning and a VISIBLE end. U+3-+45A/re/PI:34-0o=s is NOT a logical anything.

 

[RaynorWolfcastle]

MichaelID, you wouldn't believe the level of math that is required to solve some incredibly elementary physics problem.

For example, today in my Cal class we were learning about how to use the residues in the complex plane that result from taking a contour integral to solve inverse Laplace Transforms. Knowing that, you can use you can use Laplace transforms to solve boundary value problems that use higher order partial differential equations. What are the practical applications of all this gibberish?

- Solving for the temperature distribution in an idealized, heated metal rod
- Solving for current in an RLC circuit
- Solving for the motion of a damped oscillating block attached to a spring
and other very elementary problems

Like I said, some times a lot of math is required to solve very simple problems.

Sorry for hijacking your thread Oscar, but if I were trying to solve this problem, I'd definitely switch to polar coords. as was mentioned earlier