Calling math wizs, I need some double checking...

SithSolo1

Diamond Member
Mar 19, 2001
7,740
11
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Ok my friends and I have spent the past 15mins calculating the number of lottery combinations for 3 lotterys and this is what we came up with:

Lotto 3: Pick 3 numbers 1-9 in any combination. 9^3=729

Lotto 6: Pick 6 numbers 0-9 in any combination. 10^6=1,000,000

PowerBall: Pick 5 numbers 0-9 in any combination and then 1 more ball 1-45. 10^5= 100,000 x 45 = 4,500,000

These all seem too low, what am I missing?
 

UncleWai

Diamond Member
Oct 23, 2001
5,701
68
91
It depends if you put the ball back in to the pool.

If you don't put the ball back in, it would be 1/9 * 1/8 * 1/7
 

Moonbeam

Elite Member
Nov 24, 1999
74,460
6,691
126
You can't put the ball back in the pool because you can only pick a number once on a lotto ticket.
 

Paul180

Junior Member
Nov 8, 2000
20
0
0
There is a difference between combinations and probablility... the combinations will seem low, but most lotteries do not use 1-9... they use 1-50 which changes things alot!

http://www.alllotto.com/lottery_odds_calculator.php

That can help you out with the probability part of it, and the combinations you are doing are correct except there is no replacement
 

amnesiac

Lifer
Oct 13, 1999
15,781
1
71
Err, aren't the lotto 6 / powerball 1-51 or something?

In any case, you have to use a pick/choose formula
 

HonkeyDonk

Diamond Member
Oct 14, 2001
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0
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Lotto pick 6 numbers would be: 50 x 49 x 48 x 47 x 46 x 45 = 11,441,304,000

assuming that there are 50 numbers to chose from (1-50) and you don't put the ball back in after it has been drawn.
 

SithSolo1

Diamond Member
Mar 19, 2001
7,740
11
81
Durr I knew I was forgetting something! Lotto is like 1-45 for each number

As you can tell I have never played
 

jagr10

Golden Member
Jan 21, 2001
1,995
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Here's an example:

If you have 49 balls and 6 get picked then it's:

1/49 x 1/48 x 1/47 x 1/46 x 1/45 x 1/44 etc.

multiply all those and you won't feel so lucky.

i think i'm wrong somewhere. my number seems to high.
 

Woodchuck2000

Golden Member
Jan 20, 2002
1,632
1
0
Originally posted by: jagr10
Here's an example:

If you have 49 balls and 6 get picked then it's:

1/49 x 1/48 x 1/47 x 1/46 x 1/45 x 1/44 etc.

multiply all those and you won't feel so lucky.

i think i'm wrong somewhere. my number seems to high.
The formula for the number of ways to pick n balls from r possibilities, assuming the order matters and balls are not replaced is:
n!/r!(n-r)!
Picking six from 49 gives you about 14 million different possibilites.