calling all physicists

[causearuckus]

Is the area under a Force vs. Time graph the same as the mass time the velocity? this deals with momentum and impulse

 

[User1001]

no. It is the same as impulse which is a change in momentum

 

[KnickNut3]

Well, F*t is N*s = kg*m/s^2*s = kg*m/s which is m*v

Dimensional analysis is your friend

EDIT - I was unclear--impulse is s CHANGE in momentum. User1001 is right.
Dimensional analysis is still your friend, though

 

[pmoa]

Originally posted by: User1001
no. It is the same as impulse which is a change in momentum

:thumbsup: correct

 

[causearuckus]

thanks. so the area under the graph is the impulse?

 

[Buttzilla]

Originally posted by: causearuckus
thanks. so the area under the graph is the impulse?

yes, is this for a lab? we did this lab about 2 weeks ago.

 

[TuxDave]

Originally posted by: causearuckus
thanks. so the area under the graph is the impulse?

Yes.

And if you're given an initial momentum is zero, then impulse = momentum

 

[MichaelD]

There are no Doctorated Physicists on this board.

 

[causearuckus]

Ya its a lab. Cart and spring and photogate. thanks for the help

 

[FoBoT]

i am not a doctor, but i stayed at a holiday inn express last night

turn your head and cough, please

 

[causearuckus]

ok. i calculated the area under the curve. now it wants me to claculate and record the product of mass and change in velocity so... m*(Vf-Vi). and how should that compare to the area under the curve

 

[mwtgg]

Originally posted by: FoBoT
i am not a doctor, but i stayed at a holiday inn express last night

turn your head and cough, please

haha, sorry, I have nothing to add, but that was funny. :thumbsup:

 

[TuxDave]

Originally posted by: causearuckus
ok. i calculated the area under the curve. now it wants me to claculate and record the product of mass and change in velocity so... m*(Vf-Vi). and how should that compare to the area under the curve

..... is that a statement or a question? If you understand what an impulse meant, you shouldn't be asking this.

 

[causearuckus]

well impulse is the change in momentum, and momentum is mass*velocity, not the change in velocity.