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calculus problem

TI-89

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but on a serious note, i think you ahve to integrate outside then inside, so integral of ln is 1/(xxxxxxx)

then + integral of inside..

but i cant remember, been like 2 yrs
 
integration by parts... (integral of udv = uv - integral of v du)
let u = the whole thing, dv = dx...


Sheeeesh, 7 minutes before anyone replied with the method. 🙂 Must be I'm the only calculus teacher on ATOT at this time?
 
Originally posted by: snik
Open up your book and look there. Why do people expect Atot to do their homework?

The only reason i ask is because i cant find in my book, and im studying for final not doin hw
 
Because it's addition, you do each part on it's own (x -> 1/2x^2, x^2 -> 1/3x^3), then just put them both together.

Edit: nm, I didn't see the LN there 😱
 
Originally posted by: DrPizza
integration by parts... (integral of udv = uv - integral of v du)
let u = the whole thing, dv = dx...


Sheeeesh, 7 minutes before anyone replied with the method. 🙂 Must be I'm the only calculus teacher on ATOT at this time?

let u = ln (x + x^2)
then, du = 1/(x + x^2) * (1 + 2x)dx
dv = dx
then v = x
integral udv = uv - integral v du
= x ln(x + x^2) - integral x*(1 + 2x) dx / (x + x^2)

 
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