How do I get the volume of the slab/wedge below? I'm having a problem as to where to start in finding the integral
http://www.voidyourwarranty.net/images/trilobyte/untitled.JPG
*pretend those are uniformed curves
Thanks!
Yep, both of you!Originally posted by: trilobyte
Calculus Lovers, I'm calling you out!!
Imagine a plane intersecting all the way through the bottom right portion of the cylinder. He needs to find the volume of the small "wedge" cut out of the cylinder.Originally posted by: GoodToGo
Umm I dont get the picture. Is the cylinder "torn" or what?
Originally posted by: trilobyte
???
i appreciate the help, but that makes to sence in terms of setting up the integral
Originally posted by: Evadman
Ok , lets make it easy then.
To make it easier I will number everything. New sections numbered
The angle is 45 degrees.
The radius is 2
usee your nifty graphing calculator to find the length of A. B is the bottom of that triangle, which is also the radius r. Since that angle is a nice 45 degrees, then we know without a calculator, that A is exactly 1/2 of the radius, or bottom of the triangle. or 1.
D is the diameter, or 2r. So we get 4.
So we have:
A= 1
B= 2
Using pathagreans therom, 1^2 + 2^2 = C^2 or C = square root 5. (2.2306)
A= 1
B= 2
C= 2.2306
D= 4
Now we figure out the section of cylander that A goes up to. You have the height, 1. And you have the radius, 2. Then you can figure out the volume in that cylinder. this part
Then, ( and this is the part I just made up, but It should work) take the degree from that angle, and take it as a percentage of 180. Or in this instance, 45 / 180 = .25 or 25% then, multiply the voluem you got earlier by .25 and you should get your answer.
Originally posted by: Evadman
rgwalt:
Your right. It will always be 1/4 of the smaller cyl. Its been to long
then the formula can just be:
pi r^2 * A) * .25
Originally posted by: rgwalt
Originally posted by: Evadman
rgwalt:
Your right. It will always be 1/4 of the smaller cyl. Its been to long
then the formula can just be:
pi r^2 * A) * .25
I'm not so sure that it is 1/4 after giving it more thought though... it would work just fine if it was a rectangular prism, but since it is a cylinder, I don't think it is right.
trilobyte: Do you have any idea of the equations of the curves?
Ryan
