I've been spending the last hours trying to find out what the derivative of f(x)=x^x^x
what i have right now is
dy/dx =(x^x * ln^2x + x^x * lnx + x^(x-1))x^x^x
But for some reason i think i am missing a chain rule...
Any help would be great!!!
Thanks
Aganack
what i have right now is
dy/dx =(x^x * ln^2x + x^x * lnx + x^(x-1))x^x^x
But for some reason i think i am missing a chain rule...
Any help would be great!!!
Thanks
Aganack
