Fayd
Diamond Member
So a local grocery store has a lame promotion right now where you get a card with 9 things to scratch off. You can only scratch off 3 and if you happen to get the right 3 that match, you win something.
First scratch you can get any of the winning 3 from the 9.
Second scratch you can get either of the remaining 2 from the 8.
Third scratch you have to get the last one from the 7
I haven't done statistics for years but to calculate that would you do:
3/9 * 2/8 * 1/7 which his about 1%?
Or is that wrong?
simple hyper-geometric model.
(3,3)(6,0)/(3+6,3) = 1/9c3 = 1/84
with this model i can also calculate the probability of getting 1 wrong, 2 wrong, and just completely fucking up.
(3,2)(6,1)/(3+6,3) = 3*6/84 = 18/84
(3,1)(6,2)/(3+6,3) = 3*15/84 = 45/84
(3,0)(6,3)/(3+6,3) = 1*20/84 = 20/84
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