(C++) How do I access elements of a structure from a function where the element isn't declared?

[BigToque]

In one of my functions, I've declared a structure.

I want to be able to modify the contents of that structure (specifically an array I've defined) from another function, but I keep getting an error saying my structure is undeclared.

How do I go about doing this?

 

[Barnaby W. Füi]

Declare the struct outside of the function, where both can see it.

 

[BigToque]

Originally posted by: BingBongWongFooey
Declare the struct outside of the function, where both can see it.

Wouldn't that make it global?

I thought declaring global variables was considered "bad pratice". Is that false?

 

[oog]

it's not clear to me what you're doing. if you have a struct declared outside of your function and you then declare a variable whose type is that struct, then you should be able to pass the variable to another function and have it manipulate the public members of that variable (assuming that the 2nd function knows what the struct looks like).

 

[BigToque]

Here is my thread on cprogramming.com. I find the

 tag to be better then the one here and is easier to read. It should give you a better idea of what I'm trying to do.

[url="http://cboard.cprogramming.com/showthread.php?t=63323"]Post[/url]

 

[Barnaby W. Füi]

A struct definition is not a variable, so no, it's not a global variable. And you can also declare it at the namespace or class scope if it matters to you.

 

[TheLonelyPhoenix]

Pass a pointer to the struct to the function you want to modify it.

You could also declare the struct as a global variable, but you're right, that is horrible programming practice.